Remember
(x^m)/(x^n)=x^(m-n)

(q^(33/4))/(q^8)=q^((33/4)-8)
what is 33/4-8?
33/4-8=33/4-32/4=1/4

result is
q^1/4 or $\sqrt[4]{q}$

answer is $q^{ \frac{1}{4} }$

8 0

3 years ago

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What is the equation of the line below?

Licemer1 [7]

Answer:

$y = -\frac{2}{3}x + 1$

Step-by-step explanation:

The equation of the line shown can be expressed in the slope-intercept formula as $y = mx + b$

Let's find m = slope, and b = y-intercept.

Using two points on the line, (0, 1) and (1½, 0),

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 1}{\frac{3}{2} - 0} = \frac{-1}{\frac{3}{2}} = - \frac{2}{3}$

y-intercept, b is where the line intercepts the y-axis = 1.

To create an equation for the line, substitute m = -⅔, b = 1 in $y = mx + b$ .

✅The equation would be:

$y = -\frac{2}{3}x + 1$

4 0

3 years ago