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kotykmax [81]
2 years ago
10

I need help plz !!!!!!!!!!!!! i dont under stand

Mathematics
1 answer:
Vikki [24]2 years ago
7 0

Answer:

b

Step-by-step explanation:

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frutty [35]

Answer:

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Step-by-step explanation:

<u>Kamille is wrong, because:</u>

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I highly recommend you use photomath for this. but i have the answer!

26-16x is the answer
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g Let G be a not necessarily abelian group with normal subgroups H and K such that H contains K (i.e., K ✂ G, H ✂ G, K ≤ H) and
allsm [11]

Answer:

Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, [ab]_K is equal to [ba]_K, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.

Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, [ab]_H = [ba]_H . Since a and b were generic elements of H, then H/G is abelian.

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3 years ago
Ab-2=3c solve for b​
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