Answer:
(10,2)(20,4)(30,6)(40,8)
Step-by-step explanation:
In each bracket the first digit divided by the second is equal to 5
10÷2=5
20÷4=5
30÷6=5
40÷8=5
Answer:
The graph is symmetric about the origin.
The graph does not pass through the origin.
Step-by-step explanation:
We're given:
- the function y=axn
- a = 1
- n is odd
Because a = 1, then the given function can be rewritten as y = n.
The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.
- The graph is symmetric about the origin.
This is true, given the graph is a horizontal line.
- The graph does not pass through the origin.
This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.
- The graph has more than one x-intercept.
This would only be true when n = 0, and this isn't possible. So, no.
The answer is 135 because the angle equals 180 by itself and 180 subtracted from 45 is 135 .. I hope this is helpful
Answer:
A
Step-by-step explanation:
because the answer is A
Answer:

Step-by-step explanation:
Using central Limit Theorem (CLT), The sum of 100 random variables;
is approximately normally distributed with
Y ~ N (100 ×
) = N ( 50,
)
The approximate probability that it will take this child over 55 seconds to complete spinning can be determined as follows;
N ( 50,
)




Using Chebyshev's inequality:

Let assume that X has a symmetric distribution:
Then:


where: (
)
