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dangina [55]
3 years ago
8

Help me someone pleaseee

Mathematics
1 answer:
quester [9]3 years ago
6 0
OOF that looks hard...
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Find the product of −1 and −3
Lesechka [4]

Step-by-step explanation:

the product of −1 and −3

(-1)×(-3)

= 3

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Help me please <br> i need this for now
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The main property is  as follow
(A^p)^q=A^pxq
so only Sam's work is correct because
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What are the factors of the expression (y-2)(x+3)
mr Goodwill [35]
The factors of the expression is 2and -3
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Find the Diameter of the Circle with the following equation. Round to the nearest tenth.
Radda [10]

The diameter of the circle is 11.8 units

<h3>How to determine the diameter of the circle?</h3>

The circle equation is given as:

(x - 2)^2 + (y + 6)^2 = 35

A circle equation is represented as:

(x - a)^2 + (y - b)^2 = r^2

Where

Diameter = 2r

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r^2 = 35

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3 0
2 years ago
Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1
kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

<u>Background of the Discriminant</u>

The discriminant b^2-4ac applies to quadratic equations when they are organised in standard form: ax^2+bx+c=0.

All quadratic equations can be solved with the quadratic formula: x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}.

When b^2-4ac is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

<u>Solving the Problem</u>

<u />3x^2+5x=-1<u />

We're given the above equation. It hasn't been organised completely in ax^2+bx+c=0, but we can change that by adding 1 to both sides to make the right side equal to 0:

3x^2+5x+1=0<u />

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

4 0
3 years ago
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