Answer:
Step-by-step explanation:
The range is the difference between the highest and the lowest values in a set of data. The interquartile range, the IQR, is what's "inside" the box in a box plot, which consists of the difference between the central measures, which are the first and the third quartiles.
Answer:
C
Step-by-step explanation:
cos(theta) is positive in IV quadrant and sin(theta)=sqrt(13^2-5^2)/13=-12/13
Answer:
f(n) = -n^2 -3n +5
Step-by-step explanation:
Suppose the formula is ...
f(n) = an^2 +bn +c
Then we have ...
f(1) = 1 = a(1^2) +b(1) +c
f(2) = -5 = a(2^2) +b(2) +c
f(3) = -13 = a(3^2) +b(3) +c
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Here's a way to solve these equations.
Subtract the first equation from the second:
-6 = 3a +b . . . . . 4th equation
Subtract the second equation from the third:
-8 = 5a +b . . . . . 5th equation
Subtract the fourth equation from the fifth:
-2 = 2a
a = -1
Then substituting into the 4th equation to find b, we have ...
-6 = 3(-1) +b
-3 = b
and ...
1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation
5 = c
The formula is ...
f(n) = -n^2 -3n +5
Answer:
hello!!!
We will learn it simple method,we know that multiplication of whole numbers is repeated addition. For example
3*4= 4+4+4
in this same way we can say that
[-12]=(-3)+(-3)+(-3)+(-3)
also,
4(*-3)=(-12)
for the second equation we can take it same as the above one
So it make no diffrence when we multiplied integers as (positive)*(negative) OR (NEGATIVE)*(POSITIVE)
And so now we can say
FOR ANY TWO POSITIVE INTEGER a and b WE CAN SAY
(-a) *(b) = (-b)*(a) = -(a*b)
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