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Bond [772]
3 years ago
7

Here have some points

Mathematics
2 answers:
Lisa [10]3 years ago
8 0

Answer:

bet thanks

Step-by-step explanation:

kozerog [31]3 years ago
5 0

Answer:

Cheers bro ;)

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What is the slope of a line parallel to the line y = 2x -1?
Nutka1998 [239]

Answer:

2x

Step-by-step explanation:

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3 0
2 years ago
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Solve the equation for x: c a−x/x−a =5x Answer: , a ≠ − 1/5
meriva

Answer:

\large\boxed{x=-\dfrac{1}{5}}

Step-by-step explanation:

\dfrac{a-x}{x-a}=5x\\\\\dfrac{(a-x)}{-(a-x)}=5x\qquad\text{cancel}\ (a-x)\\\\-1=5x\qquad\text{divide both sides by 5}\\\\-\dfrac{1}{5}=\dfrac{5x}{5}\to\boxed{x=-\dfrac{1}{5}}

7 0
3 years ago
The volume of a cube is 8in to the 3 how long is each side
Alex777 [14]
It is 24in cube value 8 times 3 equals 24
3 0
3 years ago
Luigi is an urban planner. As an independent contractor, he charges a $140 fee plus $25 per hour for
Anuta_ua [19.1K]

Answer:

Function: y=140+25x

Amount earned for 10 hours of work: \$390

Step-by-step explanation:

Let be "x"  the number of hours worked on a project and "y" the total amount Luigi charges for a project.

Based on the data given in the exercise, you can identify that:

  • $140 is a fixed amount.
  • For each hour worked on the project, Luigi charges $25. This can be expressed as: 25x

Then, the total amount he charges for a project is the sum of $140 and 25x. This can be represented with the following function:

y=140+25x

To calculate the amount of money earned for 10 hours of work, you must substitute x=10 into the function and evaluate. Then:

y=140+25(10)\\\\y=390

7 0
3 years ago
Sec s = 1.6948
Anastaziya [24]
That'd be true only if the value of "s" is the exact same one for both
namely  if sec(s) = cos(s)
then solving for "s"
thus

\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)}
\\\\\\
thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s)
\\\\\\
\pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides}
\\\\\\
cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s
5 0
3 years ago
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