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maksim [4K]
3 years ago
15

PLZ HELP, GIVING BRAINLIEST!!

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0
It would be c because that is what goes
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trapecia [35]

Answer:

c

Step-by-step explanation:

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3 years ago
Use long division to find the value of 1,875÷15.
SashulF [63]

Answer:

125

Step-by-step explanation:

1875 / 15 = 125

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4 0
3 years ago
Read 2 more answers
Which of the following best completes the proof showing that ΔWXZ ~ ΔXYZ?
skelet666 [1.2K]

Angles formed by the segment \overline{XZ} in the triangles ΔWXZ, and ΔXYZ, are equal and the given corresponding sides are proportional.

  • The option that best completes the proof showing that ΔWXZ ~ ΔXYZ is; <u>16 over 12 equals 12 over 9</u>

Reasons:

The proof showing that ΔWXZ ~ ΔXYZ is presented as follows;

Segment \overline{XZ} is perpendicular to segment \overline{WY}

∠WZX and ∠XZY are right angles by definition of \overline{XZ}  perpendicular to \overline{WY}

∠WZX in ΔWXZ = ∠XZY in ΔXYZ = 90° (definition)

\displaystyle \frac{WZ}{XZ} = \frac{16}{12} = \mathbf{ \frac{4}{3}}

\displaystyle \mathbf{ \frac{XZ}{ZY}}  = \frac{12}{9}  = \frac{4}{3}

Therefore;

  • \displaystyle \frac{16}{12} = \frac{12}{9}, which gives, \displaystyle \mathbf{\frac{WZ}{XZ} }= \frac{XZ}{ZY}

Given that two sides of ΔWXZ are proportional to two sides of ΔXYZ, and

that the included angles between the two sides, ∠WZX and ∠XZY are

congruent, the two triangles, ΔWXZ and ΔXYZ are similar by Side-Angle-

Side, SAS, similarity postulate.

The option that best completes the proof is therefore;

  • \displaystyle \frac{16}{12} = \frac{12}{9} which is; <u>16 over 12 equals 12 over 9</u>

Learn more about the SAS similarity postulate here:

brainly.com/question/11923416

4 0
3 years ago
Write the factors of a2-b2.​
nignag [31]
Answer:
(a + b) and (a - b)
3 0
4 years ago
SAT scores are normally distributed with a mean of 1,500 and a standard deviation of 300. An administrator at a college is inter
Rama09 [41]

Answer:

The administrator should sample 968 students.

Step-by-step explanation:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.88}{2} = 0.06

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.06 = 0.94, so Z = 1.555.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Standard deviation of 300.

This means that n = 300

If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample?

This is n for which M = 15. So

M = z\frac{\sigma}{\sqrt{n}}

15 = 1.555\frac{300}{\sqrt{n}}

15\sqrt{n} = 300*1.555

Dividing both sides by 15

\sqrt{n} = 20*1.555

(\sqrt{n})^2 = (20*1.555)^2

n = 967.2

Rounding up:

The administrator should sample 968 students.

5 0
3 years ago
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