All categories

2 years ago

7th grade math question, awarding brainliest! 80 POINTS!!!

Mathematics

1 answer:

aivan3 [116]2 years ago

5 0

Answer:

first one

9. x-4

12. is one. 6 is another proportion now u can compare them

You might be interested in

Make a table of values for each eqution y = |x| + 1

Alisiya [41]

No x-intercept/Zero
y=1

Hope I can help you!

4 0

2 years ago

One math class has a greater number of students than the other. However,

Elden [556K]

The classes could each have proportions of 5 boys to 6 girls, but they don’t necessarily have to be exactly 5 to 6. The number could 5 to 6 for one class, but it could also be 10 to 12 for another class, since 10 to 12 is a scale factor of 5 to 6.

4 0

2 years ago

Read 2 more answers

5/6 of all the money in Salma's bank account is ₹55,000. how much money does Salma have in her bank account?

Vedmedyk [2.9K]

Answer:

₹66,000

Step-by-step explanation:

If 5/6 is 55,000 then just multiply 55,000 by the reciprocal 6/5 to get 66,000

8 0

1 year ago

Como resolver y=1-2.5

oksian1 [2.3K]

I don't really speak Spanish but I'll guess that says

How do I solve y = 1 - 2.5

Unless I'm missing something, there's not even any algebra here.

The way we subtract a bigger number from a smaller number is first we subtract the smaller number from the bigger number the regular way, then we prepend a minus sign.

y = 1 - 2.5 = -(2.5 - 1) = -1.5

7 0

3 years ago

How does the sample size affect the validity of an empirical argument? A. The larger the sample size the better. B. The smaller

astra-53 [7]

Answer:

A. The larger the sample size the better.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

We have to look at the standard error, which is:

$s = \frac{\sigma}{\sqrt{n}}$

This means that an increase in the sample size reduces the standard error, and thus, the larger the sample size the better, and the correct answer is given by option a.

7 0

2 years ago