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3 years ago

A circle has a circumstance of 22cm what’s the radius using pi

Mathematics

1 answer:

atroni [7]3 years ago

7 0

Answer:

3.50

Step-by-step explanation:

C = 2πr

C = πd

In this case we are using C = 2πr

C = 2πr

22 = 2 x 3.14 x r

22 = 6.28 x r

22/6.28 = 6.28r/6.28

3.503184713375796178343949044585987261 = r

But estimated is 3.50

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<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B

ankoles [38]

$\bold{Heya!}$

Your answer to this is:

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u /> $\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)$

$\sf{Apply \: rule:} \: (a) = a$

$\sf{(1) = 1$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1$

$\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}$

$\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

Hopefully This Helps ! ~

#LearnWithBrainly

$\underline{Answer :}$

<em>Jaceysan ~</em>

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