Answer:
<u>Part A</u>
- Reflect over the y-axis: (x, y) → (-x, y)
A (-4, 4) → (4, 4)
B (-2, 2) → (2, 2)
C (-2, -1) → (2, -1)
D (-4, 1) → (4, 1)
- Shift 4 units down: (x, y-4)
(4, 4-4) → A' (4, 0)
(2, 2-4) → B' (2, -2)
(2, -1-4) → C' (2, -5)
(4, 1-4) → D' (4, -3)
<u>Part B</u>
Two figures are <u>congruent</u> if they have the same shape and size. (They are allowed to be rotated, reflected and translated, but not resized).
Therefore, ABCD and A'B'C'D' are congruent. They are the same shape and size as they have only be reflected and translated.
Answer:
Yellow is correct.
You can add the valued and divide by how many values there are to find the mean
The score of 20 is an outlier and brings the mean score down by almost 10%
Step-by-step explanation:
Answer: It is TRUE. A point in a linear equation can be the solution to said equation.
Step-by-step explanation:
See the attached for the proof
The domain and range for each line is all real numbers. This is because all numbers are possible to input into x and all y values exist.
The slope of the first line is -2/3 and the y intercept is 6. You can reach this conclusion by solving for y (putting it in slope intercept form).
The slope of the second one is 3/4. and the y intercept is all real numbers greater than -4. This is true because it is an inequality and you can find these numbers by solving for y.
