Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!
Answer: Rectangle
Reasoning: 4 straight sides, 2 pairs of sides of equal length.
Answer: 7 Boxes
Step-by-step explanation:
There are 4 classrooms and 29 boxes of markers. So, you would divide 29 by 4 which is 7.25. Then, you need to round it because you don't have a quarter of a box. So, each classroom will get 7 boxes.
I hope that helps!
Answer:
200
Step-by-step explanation:
200×4%=8
8×3=24
The original amount is $200
ONO THAT NOT THE ANSWER THIS IS [3,628,800] 10P10=10, AND 0!= 10 TIMES 9 TIMES 8 TIMES 7 TIMES 6 TIMES 5 TIMES 4 TIMES 3 TIMES 2 TIMES 1= 3,628,800.
