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atroni [7]
2 years ago
9

Social support and stroke-induced aphasia. Hilari and Northcott (2006) used a Social Support Survey (SSS) to gauge how well-supp

orted individuals suffering from stroke-induced aphasia (a language disorder) felt more than one year following the stroke. They reported that “in terms of social support, the SSS scores were negatively skewed with a mean of 3.69, suggesting that participants felt overall well supported” (Hilari & Northcott, 2006, p. 17). Based on their findings, what additional measure of central tendency would be appropriate to report with these data?
Explain.
Mathematics
1 answer:
Nana76 [90]2 years ago
3 0

Answer:

A third metric to consider is the median. The reason for this is that all of the data is negatively skewed, and using mean would result in a reduction.

Step-by-step Explanation:

Okay, So for this problem, we were asked to make a relative frequency distribution based office of this clinical trial for this drug and its adverse side effects. Okay, so, um, that's look at the data here. We'll make a relative frequency distribution as a chart with two sides over here, we will write thes side effects. So I defects. Over here, we will write the frequency of those side effects. Okay, so we have headaches. Eggs. There was hypertension, a pretension, upper respiratory infection. A margarita, as you are. A per respiratory nasal Farron Ghitis. It's just right neighs o on then. Lastly, there was diarrhea. Okay, So the frequencies for these, we were told, were 57 in 21 60 51 and 53. Okay, so that is the frequency distribution right there. That's the first part of our answer. Okay, Second part of our answer says, are any of these, um, more common than the other? That's has to use relative frequency. Okay, So for relative frequency, relative frequency, it's just equal to the individual frequency f over the some summation symbol right there of the frequencies. Okay. And from that we'll get a percentage if we times it by 100%. Yeah. Cool. So, um, what is the sum of all these frequencies? Some of all the frequencies. It's just equal to 57 plus 21 plus 60 plus 51 plus 53. And that is just 242. So if I wanted to get the relative frequency for headaches, um, which I will do right now, let me switch colors to do that, do that and read on. So the relative frequency for headaches it's equal to 57 over 2 42 times, 100%. And when I do that, I get about 23%. So 23% Okay, I do it for the next one. I'll dio 21 divided by 2 42 times 100%. This is for hypertension. I get approximately 9%. Okay, So frequency of hypertension is 9%. It's a lot less than the headaches. Let's do the rest. So 60 divided by 2 42 times 100% equal to about 25%. And then the 51 divided by 2. 42 times 100% approximately 21% and then last 1 53 developed by 2 42 times 100% approximately 22%. Okay, fill out our chart here. So well, we have 25% for a respiratory. 51 21% for needs affair and itis. And then lastly for diarrhea, 22%. Okay, So the question asked us, um if any one of these air more common than the other Not really. There's less for hypertension, but they're all about more or less the same, so there is no difference or no prevalence of adverse side effects.

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bagirrra123 [75]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

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3 years ago
If the point P(-4/5,y) lies on the unit circle and P is in the third quadrant, what does y equal? If necessary, use the slash ma
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