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Dmitry [639]
4 years ago
11

3x + 8y = 28 3x + 2y = 4 Find both the x and y coordinates

Mathematics
2 answers:
umka2103 [35]4 years ago
6 0

Answer:

(- \frac{4}{3}, 4 )

Step-by-step explanation:

Given the 2 equations

3x + 8y = 28 → (1)

3x + 2y = 4 → (2)

Subtracting (2) from (1) term by term will eliminate the x- term

(3x - 3x) + (8y - 2y) = (28 - 4), that is

6y = 24 ( divide both sides by 6 )

y = 4

Substitute y = 4 into either of the 2 equations and solve for x

Substituting into (1)

3x + 8(4) = 28

3x + 32 = 28 ( subtract 32 from both sides )

3x = - 4 ( divide both sides by 3 )

x = - \frac{4}{3}

Solution is (- \frac{4}{3}, 4 )

Aleksandr-060686 [28]4 years ago
3 0

If you subtract the two equations you get

\underbrace{(3x + 8y)-(3x + 2y)}_{\text{Difference of the LHS}}=\underbrace{28-4}_{\text{Difference of the RHS}}

This can be simplified into

6y=24 \iff y=4

Now you can plug this value for y in one of the two equations, and solve it for x.

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Whats the area of the rectangle? ​
nevsk [136]

Answer:

<h2>24x^2-13x-2</h2>

Step-by-step explanation:

Area of rectangle = Length ×Breadth

Length =8x+1\\Breadth = 3x-2\\\\A =\left(8x+1\right)\left(3x-2\right)\\\\=8x\times\:3x+8x\left(-2\right)+1\times\:3x+1\times\left(-2\right)\\\\=8\times\:3xx-8\times \:2x+1\times \:3x-1\times\:2\\\\=24x^2-13x-2

8 0
3 years ago
. A bridge over a river is built in the shape of a parabolic arch. The bridge has a span of 100 feet. The height of the arch is
katen-ka-za [31]

Answer:

The height of the arch at its center is 250/9 or about 27.78 feet.

Step-by-step explanation:

We can write an equation to model the parabolic arch.

Let the left-most point of the arch be the origin (0, 0).

Since the bridge has a span of 100 feet, the right-most point must be (0, 100).

We can use the factored form of a quadratic:

y=a(x-p)(x-q)

Where <em>p</em> and <em>q</em> are the <em>x-</em>intercepts.

Our <em>x-</em>intercepts are <em>x </em>= 0 and <em>x </em>= 100. Hence:

y=ax(x-100)

At a point 40 feet from the center, the height of the arch is 10 feet.

The center is <em>x</em> = 50. So, a point 40 feet from the center can be either <em>x</em> = 10 or <em>x</em> = 90.

So, for instance, when <em>x</em> = 10, <em>y</em> = 10. Substitute and solve for <em>a: </em>

<em />10=10a(10-100)<em />

So:

\displaystyle a=-\frac{1}{90}

The same value will result if we let <em>x</em> = 90 and <em>y</em> = 10.

Hence, our equation is:

\displaystyle y=-\frac{1}{90}x(x-100)

The height of the arch at its center will be when <em>x</em> = 50. Hence:

y(50)=\displaystyle -\frac{1}{90}(50)((50)-100)=\frac{250}{9}\approx 27.78\text{ feet}

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