5x+10=10y <br><br><br> How to solve for y

Answers for these im strugglinh

Rainbow [258]

Answer:

Step-by-step explanation:

40.

Multiples of 3: 3,6,9,12, 15, …

Multiples of 5: 5, 10, 15, 20, …

LCM of 3 and 5 is 15

Multiples of 6: 6, 12, 18, 24,…

Multiples of 9: 9, 18, 27,…

LCM of 6 and 9 is 18

42.

1/2 and 2/3

denominator 2 has multiples: 2, 4, 6, 8, 10, 12 …

denominator 3 has multiples: 3, 6, 9, 12,…

LCD of 1/2 and 2/3 is 6

equivalent fraction 1/2 = 3(1/2) = 3/6

equivalent fraction 2/3 = 2(2/3) = 4/6

43.

5/12 and 2/15

denominator 12 has multiples: 12, 24, 36, 48, 60…

denominator 15 has multiples: 15, 30, 45, 60…

LCD of 5/12 and 2/15 is 60

equivalent fraction 5/12 = 5(5/12) = 25/60

equivalent fraction 2/15 = 4(2/15) = 8/60

44.

16/48 has the prime factorization 2*2*2*2/ 2*2*2*2*3

16/48 simplification is 1/3

45.

12/40 has the prime factorization 2*2*3/2*2*2*5

12/40 simplification is 3/ 10

46.

18/63 has the prime factorization 2*3*3/ 3*3*7

18/63 simplification is 2/7

5 0

3 years ago

A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.

zmey [24]

Answer:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=2.2$ represent the sample mean

$s=0.29$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =2.1$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.1$

Alternative hypothesis: $\mu > 2.1$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0

4 years ago

Help me I’ll mark brainliest!!!!

katrin2010 [14]

Answer:

Sorry no idea

Step-by-step explanation:

I'm so sorry

3 0

3 years ago

Read 2 more answers

A video company randomly selected 100 of its subscribers and asked them how many hours of shows they watch per week. Of those su

Alik [6]

Answer:

1,135 people

For every 100 people only 45 people watch more than 10 hours per week. So, the ratio is (45/100), since the company has 2500 we want to know what (x/2500) is. The total ratio becomes (1,135/2,500).

The number is found by dividing 2500 by 100 to receive the common factor of 25. You multiply 45 by 25 to receive your total answer.

Step-by-step explanation:

For every 100 people only 45 people watch more than 10 hours per week. So, the ratio is (45/100), since the company has 2500 we want to know what (x/2500) is. The total ratio becomes (1,135/2,500).

The number is found by dividing 2500 by 100 to receive the common factor of 25. You multiply 45 by 25 to receive your total answer.

8 0

3 years ago

A college student with a bachelors degree in nursing from an accredited institution has an 86.74% chance of getting hired full t

Vladimir79 [104]

Answer:

86.74% probability of a Madonna University nursing student getting hired within 6 months of graduation given that they complete their degree here.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Compute the probability of a Madonna University nursing student getting hired within 6 months of graduation given that they complete their degree here.

In this problem, we have that:

Event A: Completing their degree there.

There is a 34.72% chance of a student interested in a nursing degree not making it through the program.

So 100 - 34.72% = 65.28% = 0.6528 probability of completing their degree. So P(A) = 0.6528.

Event B: Getting hired

86.74% chance of getting hired full time in a hospital setting within 6 months of graduation.

Completing their degree and getting hired:

$P(A \cap B) = 0.6528*0.8674$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.6528*0.8674}{0.6528} = 0.8674$

86.74% probability of a Madonna University nursing student getting hired within 6 months of graduation given that they complete their degree here.

5 0

3 years ago

5x+10=10y How to solve for y