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3 years ago

What is the variable x

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

3 0

X =3 hope it helps..................................

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Which of the following statements are mathematical statement?

kvv77 [185]

Answer:

a is the right answer atleast that's what I think

3 0

3 years ago

Read 2 more answers

Someone help solve ill gift you nitro :)

Tems11 [23]

1/3•3.14•. r^2 •h

1/3•3.14•20^2•25

10466.6667

that rounds up to 10,467.

I could be wrong though!

hope this helps! :)

7 0

2 years ago

The picture shows a circular clock face.

marysya [2.9K]

Answer:

[C] 25π square inches

Step-by-step explanation:

Given that:

the long hand of the clock is about 5 inches long.

To Find:

What is the approximate area of the clock face?

Solve:

Formula - A =πr²

Note that;

π = 3.14 (about)

Radius - 5 inches

A =πr²

A = 3.14(5)²

A = 3.14(25)

A = 78.5

Now let see the answer choices:

A. 5π square inches ≈ 5(3.14) = 15.7

B. 10 π square inches ≈ 10(3.14) = 31.4

C. 25 π square inches ≈ 25(3.14) = 78.5

D. 100 π square inches ≈ 100(3.14) = 314

Hence, the answer is [C] 25 π square inches

Kavinsky~

6 0

1 year ago

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How many centimeters are in 3.2 inches? [1 inch = 2.5 cm]

garik1379 [7]

There are about 8cm in 3.2 inches

6 0

3 years ago

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Find the perimeter of WXYZ. Round to the nearest tenth if necessary.

yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

$W(-1, 1) = (x_1, y_1)$

$X(1, 2) = (x_2, y_2)$

Plug in the values

$WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}$

$WX = \sqrt{(2)^2 + (1)^2}$

$WX = \sqrt{4 + 1}$

$WX = \sqrt{5}$

$WX = 2.24$

✔️Distance between X(1, 2) and Y(2, -4)

Let,

$X(1, 2) = (x_1, y_1)$

$Y(2, -4) = (x_2, y_2)$

Plug in the values

$XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}$

$XY = \sqrt{(1)^2 + (-6)^2}$

$XY = \sqrt{1 + 36}$

$XY = \sqrt{37}$

$XY = 6.08$

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

$Y(2, -4) = (x_1, y_1)$

$Z(-2, -1) = (x_2, y_2)$

Plug in the values

$YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}$

$YZ = \sqrt{(-4)^2 + (3)^2}$

$YZ = \sqrt{16 + 9}$

$YZ = \sqrt{25}$

$YZ = 5$

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

$Z(-2, -1) = (x_1, y_1)$

$W(-1, 1) = (x_2, y_2)$

Plug in the values

$ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}$

$ZW = \sqrt{(1)^2 + (2)^2}$

$ZW = \sqrt{1 + 4}$

$ZW = \sqrt{5}$

$ZW = 2.24$

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0

3 years ago