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damaskus [11]
3 years ago
13

What is the variable x

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
3 0
X =3 hope it helps..................................
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Which of the following statements are mathematical statement?
kvv77 [185]

Answer:

a is the right answer atleast that's what I think

3 0
3 years ago
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Someone help solve ill gift you nitro :)
Tems11 [23]
1/3•3.14•. r^2 •h

1/3•3.14•20^2•25

10466.6667

that rounds up to 10,467.

I could be wrong though!

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7 0
2 years ago
The picture shows a circular clock face.
marysya [2.9K]

Answer:

[C] 25π square inches

Step-by-step explanation:

<u><em>Given that:</em></u>

<em>the long hand of the clock is about 5 inches long.</em>

<u><em>To Find:</em></u>

<em>What is the approximate area of the clock face?</em>

<u><em>Solve:</em></u>

<em>Formula - </em><em>A =πr²</em>

<em>Note that;</em>

<em>π = 3.14 (about)</em>

<em>Radius - 5 inches</em>

<em>A =πr²</em>

<em>A = 3.14(5)²</em>

<em>A = 3.14(25)</em>

<em>A = 78.5</em>

<em>Now let see the answer choices:</em>

<em>A.  5π square inches                     ≈   5(3.14) = 15.7</em>

<em>B. 10 π square inches                    ≈  10(3.14) = 31.4</em>

<em>C. 25 π square inches                    ≈  25(3.14) = 78.5</em>

<em>D. 100 π square inches                    ≈ 100(3.14) = 314</em>

<em />

<em>Hence, the answer is [C] 25 π square inches </em>

<em />

<u><em>Kavinsky~</em></u>

6 0
1 year ago
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garik1379 [7]
There are about 8cm in 3.2 inches
6 0
3 years ago
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Find the perimeter of WXYZ. Round to the nearest tenth if necessary.
yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

W(-1, 1) = (x_1, y_1)

X(1, 2) = (x_2, y_2)

Plug in the values

WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}

WX = \sqrt{(2)^2 + (1)^2}

WX = \sqrt{4 + 1}

WX = \sqrt{5}

WX = 2.24

✔️Distance between X(1, 2) and Y(2, -4)

Let,

X(1, 2) = (x_1, y_1)

Y(2, -4) = (x_2, y_2)

Plug in the values

XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}

XY = \sqrt{(1)^2 + (-6)^2}

XY = \sqrt{1 + 36}

XY = \sqrt{37}

XY = 6.08

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

Y(2, -4) = (x_1, y_1)

Z(-2, -1) = (x_2, y_2)

Plug in the values

YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}

YZ = \sqrt{(-4)^2 + (3)^2}

YZ = \sqrt{16 + 9}

YZ = \sqrt{25}

YZ = 5

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

Z(-2, -1) = (x_1, y_1)

W(-1, 1) = (x_2, y_2)

Plug in the values

ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}

ZW = \sqrt{(1)^2 + (2)^2}

ZW = \sqrt{1 + 4}

ZW = \sqrt{5}

ZW = 2.24

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0
3 years ago
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