Find the perimeter of △ABC with vertices A(−4, 3), B(1, −5), and C(−4, −5). Round your answer to the nearest hundredth.

1 answer:

8 0

Let's use the distance formula: $\sqrt{ (x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}$

So it is:

AB : $\sqrt{(-5)^2 + 8^2} = 9.43$
BC: $\sqrt{5^2 + 0^2 } = 5$
CA: $\sqrt{0^2 + 8^2} = 8$

So 9.43 + 5 + 8 =22.43

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