Does anyone know what 3m−7=5 is?
2 answers:
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Take an arbitrary vector (<em>x</em>, <em>y</em>, <em>z</em>), which goes from the origin to some point (<em>x</em>, <em>y</em>, <em>z</em>) on the plane we want to find.
Subtract from this vector, the vector that points to , which is (-3, 3, 1). This translates the first vector so that it starts at the point
and is directed at some point (<em>x</em>, <em>y</em>, <em>z</em>). We get a new translated vector, (<em>x</em> + 3, <em>y</em> - 3, <em>z</em> - 1), which lies in the plane.
The normal vector to the plane is orthogonal to every vector in the plane. So taking the dot product of any vector in the plane with the normal to the plane will always result in 0. We use this to find the plane's equation:
and so the answer is D.
Given :
A function , x = 2cos t -3sin t .....equation 1.
A differential equation , x'' + x = 0 .....equation 2.
To Find :
Whether the given function is a solution to the given differential equation.
Solution :
First derivative of x :
Now , second derivative :
( Note : derivative of sin t is cos t and cos t is -sin t )
Putting value of x'' and x in equation 2 , we get :
=(-2cos t + 3sin t ) + ( 2cos t -3sin t )
= 0
So , x'' and x satisfy equation 2.
Therefore , x function is a solution of given differential equation .
Hence , this is the required solution .