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3 years ago

A rectangle has a width of 46 centimeters and a perimeter of 204 centimeters. What is the rectangle’s length?

Mathematics

1 answer:

Vanyuwa [196]3 years ago

7 0

Answer:

Length = 56

Step-by-step explanation:

Perimeter = Length + Length + Width + Width

Perimeter = 2L + 2W

2L + 2W = 204

2L + 2(46) = 204

2L + 92 = 204

Subtract 92 from both sides

2L = 112

Divide both sides by 2

L = 56

Length = 56

You might be interested in

Describe the transformations necessary to transform f(x) into g(x)

Aleks [24]

Using translation concepts, the transformations are given as follows:

a) The function is horizontally compressed by a factor of 3 and shifted down one unit.

b) The function is shifted right 3 units and vertically stretched by a factor of 2.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

Item a:

The transformations are:

x -> 3x, hence the function is horizontally compressed by a factor of 3.

y -> y - 1, hence the function is shifted down one unit.

Item b:

The transformations are:

x -> x - 3, hence the function is shifted right 3 units.

y -> 2y, hence the function is vertically stretched by a factor of 2.

More can be learned about translation concepts at brainly.com/question/4521517

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6 0

1 year ago

I need help like fast i am on 3 and i do not know what to do

Elis [28]

Answer:

Number 3 has no solution

Step-by-step explanation:

First you need to divide both sides of the equation 12x - 12y = -12 by 4

-3x + 3y = -3

12x - 12y = -12

-3x + 3y = -3

3x - 3y = -3

Then you need to eliminate one variable by adding the equations.

0 = -6

this statement is false, and therefore has no solution.

7 0

2 years ago

if the breadth of rectangle in one third of its length and perimeter is 80 cm find length and breadth of rectangle

LiRa [457]

Answer:

length = 30 cm

Breadth = 10 cm

Step-by-step explanation:

Length = x cm

Breadth = (1/3)x

Perimeter = 80 cm

2(length + breadth) = 80

2* (x + (1/3)x) = 80

$2*(\frac{3}{3}x+\frac{1}{3}x) = 80\\\\2*(\frac{4}{3}x) = 80\\\\\frac{8}{3}x = 80\\\\x = 80*\frac{3}{8}\\\\x = 10*3$

x = 30cm

length = 30 cm

breadth = $\frac{1}{3}*30=10$ cm

6 0

2 years ago

An archaeologist uses an accelerator mass spectrometer to find the age of a buried branch. At the 68\%68%68, percent confidence

Komok [63]

Answer:

B. 10000 years old, with a margin of error of 400 years

Step-by-step explanation:

Assuming this complete problem: "12. An archaeologist uses an accelerator mass spectrometer to find the age of a buried branch. At the 68% confidence level, the spectrometer estimates that the branch was 10,000 years old with a following could the spectrometer estimate as the age of the branch at the 95% confidence level?"

The possible options are:

A. 9500 years old, with a margin of error of 500 years

B. 10000 years old, with a margin of error of 400 years

C. 9500 years olds, with a margin of error of 50 years

D. 10000 years old, with a margin of error of 40 year

Solution to the problem

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The margin of error for this case is given by this formula:

$ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

For the first case the confidence was 68% so then $\alpha =1-0.68 =0.32$ and $\alpha/2 =0.16$ we can find a critical value on the normal standard distribution that accumulates 0.16 of the area on each tail and this value is $z=\pm 0.994$ , because P(z<-0.944) = 0.16 and P(Z>.944) = 0.16

The margin of error can be expressed like this:

$ME = z_{\alpha/2} SE$

We can solve for the standard error on this case and we got:

$SE = \frac{ME}{z_{\alpha/2}} =\frac{200}{0.994}=201.207$

And then for the new confidence interval we need to calculate the new $z_{\alpha}$ . For the first case the confidence was 95% so then $\alpha =1-0.95 =0.05$ and $\alpha/2 =0.025$ we can find a critical value on the normal standard distribution that accumulates 0.025 of the area on each tail and this value is $z=\pm 1.96$ , because P(z<-1.96) = 0.025 and P(Z>1.96) = 0.025. So then the new margin of error would be: