Answer:
copy and paste
Step-by-step explanation:
Answer:
3n + 2
Step-by-step explanation:
-n+(-4)-(-4n)+6
= -n -4 +4n +6 [positive plus negative = negative; ∴ +(-4) = -4
=4n - n +6 - 4 negative plus negative = positive; ∴ -(-4n) = 4]
now subtract n from 4n and subtract 4 from 6
=3n + 2
Answer:
Step-by-step explanation:
y - z+6
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
Answer:
A
Step-by-step explanation:
An equation in the form y=kx represents something increasing at a constant <u>rate</u>
