Answer:
The base is 19.5.
Step-by-step explanation:
The given question is, "The perimeter of a rectangle is 58 and its base exceeds its width by 10, how long is the base?"
Perimeter = 58
Base, l = 10+b
The perimeter of a rectangle is :
P = 2(l+b)
58 = 2(10+b+b)
29 = (10+2b)
29-10 = 2b
19 = 2b
b = 9.5
Base, l = 10 + 9.5
= 19.5
Hence, the base is 19.5.
Expressions cannot <u>be solved.
</u>Although they are similar to equations, you can solve an equation, but you cannot solve an expression. You can evaluate it, simplify it, and it can have many variables, however, an expression just exists, it is not a problem that has to be solved.<u>
</u>
im pretty sure the answer is 30
Answer:
Plese read the complete procedure below:
Step-by-step explanation:
The polynomial is p(a) = (a^4 - 6a^3 + 3a^2 + 26a – 24)
a)
1 -6 3 26 -24 |<u> 1 </u>
<u> 1 -5 -2 24</u>
1 -5 -2 24 0
The remainder is zero, then (a-1) is a factor of the polynomial
b)
1 -6 3 26 -24 |<u> 2 </u>
<u> 2 -8 10 72</u>
1 -4 5 36 48
When p(a) is divided by (a-2) the remainder 28/p(a)
1 -6 3 26 -24 |<u> - 4 </u>
<u> -4 40 172 -792</u>
1 -10 43 198 -816
When p(a) is divided by (a-2) the remainder -816/p(a)
c) I attached an image of the long division below: