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Serjik [45]
2 years ago
12

Please help asap!!! i’ll rate you most brainliest

Mathematics
1 answer:
SSSSS [86.1K]2 years ago
6 0
I’m pretty sure it’s D??? But it also could be B I’m sorry :( trying to help as much as possible
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A

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3 years ago
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Simplify 2 (8r2+r)-4r
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16r^2+ 2r -4r 16r^2 - 2r 2r ( 8r -1)
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What is Q3 for this data set?
Kisachek [45]

The same as last time

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1 year ago
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Mei has 8 jars of soup. Each jar contains 300 milliliters of soup. What is the smallest pot Mei can use to heat all the soup.[PL
Kobotan [32]

Answer: A pot of 2400ml

Step-by-step explanation: Ok, mei has 8 jars, and each jar has 300ml of soup, so the total amount of soup is 8 times 300ml

N = 8*300ml = 2400ml

So the smallest pot that mei can use to heat the soup is a pot that has exactly that volume. 2400ml, (discarding the fact that the volume of the soup will change as it is heated up)

7 0
3 years ago
Find an equation for the plane that is tangent to the surface z equals ln (x plus y )at the point Upper P (1 comma 0 comma 0 ).
alexira [117]

Let f(x,y,z)=z-\ln(x+y). The gradient of f at the point (1, 0, 0) is the normal vector to the surface, which is also orthogonal to the tangent plane at this point.

So the tangent plane has equation

\nabla f(1,0,0)\cdot(x-1,y,z)=0

Compute the gradient:

\nabla f(x,y,z)=\left(\dfrac{\partial f}{\partial x},\dfrac{\partial f}{\partial y},\dfrac{\partial f}{\partial z}\right)=\left(-\dfrac1{x+y},-\dfrac1{x+y},1\right)

Evaluate the gradient at the given point:

\nabla f(1,0,0)=(-1,-1,1)

Then the equation of the tangent plane is

(-1,-1,1)\cdot(x-1,y,z)=0\implies-(x-1)-y+z=0\implies\boxed{z=x+y-1}

7 0
3 years ago
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