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dmitriy555 [2]
2 years ago
14

Which of the following is a synthesis reaction? AgNO3 + NaCl → AgCl + NaNO3 BaO + H2O → Ba(OH)2 SO3 + H2O → H2SO4 Cu + AgNO3 → A

g + CuNO3
Chemistry
2 answers:
Ira Lisetskai [31]2 years ago
6 0

Answer : The synthesis reaction are,

BaO+H_2O\rightarrow Ba(OH)_2

SO_3+H_2O\rightarrow H_2SO_4

Explanation :

Synthesis reaction : It is a type of combination reaction where the two or more  reactants combine to form a single product. In this reaction, reactant may be an element or compound and product is always compound.

From the given reactions, we conclude that

BaO+H_2O\rightarrow Ba(OH)_2

SO_3+H_2O\rightarrow H_2SO_4

These two reactions are the example of synthesis reaction.

While,

AgNO_3+NaCl\rightarrow AgCl+NaNO_3 is a double displacement reaction in which the cation and anion of two different reactants exchange their places to give two different products.

And,

Cu+AgNO_3\rightarrow Ag+CuNO_3 is a single replacement reaction in which the most reactive metal displaces the least reactive metal form its solution.

Mazyrski [523]2 years ago
3 0

SO3 + H2O → H2SO4 if im not mistaking

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How many moles of ammonia (nh3) would be produced if 2.5 moles of nitrogen (n2) reacted with excess hydrogen (h2)?
cluponka [151]
Firstly, a balanced equation has to be written for the production of ammonia (NH₃) from hydrogen gas (H₂) and nitrogen gas (N₂):
                    N₂   +   3H₂   →   2NH₃

Now, the mole ratio of N₂ : NH₃ is 1 : 2 based on the coefficients of the balanced equation.

If the moles of N₂ = 2.5 moles

   then the moles of NH₃ produced = 2.5 mol × 2 
                                                          =  5 mol

Thus, the moles of ammonia produced when 2.5 mol of nitrogen gas is combined with excess hydrogen gas is 5 mol.
6 0
3 years ago
Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o
sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is  4.50  ×  10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50  ×  10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4}  } = 0.0106 M

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%

4 0
3 years ago
If a buffer solution is 0.220 M in a weak acid ( Ka=7.4×10−5) and 0.540 M in its conjugate base, what is the pH?
valkas [14]

Answer: the pH of the solution is 4.52

Explanation:

Consider the weak acid as Ha, it is dissociated as expressed below

HA     H⁺  +  A⁻

the Henderson -Haselbach equation can be expressed as;

pH = pKa + log( [A⁻] / [HA])

the weak acid is dissociated into H⁺ and A⁻ ions in the solution.

now the conjugate base of the weak acid HA is

HA(aq) {weak acid}     H⁺(aq)  +  A⁻(aq) {conjugate base}

so now we calculate the value of Kₐ as well as pH value by substituting the values of the concentrations into the equation;

pKₐ = -logKₐ

pKₐ = -log ( 7.4×10⁻⁵ )

pKₐ = 4.13

now thw pH is

pH = pKₐ  + log( [A⁻] / [HA])

pH = 4.13 + log( [0.540] / [0.220])

pH = 4.13 + 0.3899

pH = 4.5199 = 4.52

Therefore the pH of the solution is 4.52

6 0
3 years ago
What do you expect would happen to the pressure of the gas in a container as the volume is decreased
Over [174]

Answer:

the pressure would increase

Explanation:

5 0
2 years ago
What is the main reason that the bounce height decrease.
tiny-mole [99]
Since there is loss of kinetic energy
5 0
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