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MatroZZZ [7]
3 years ago
11

If you made a three-dimensional model of an atom and its nucleus, how would you represent the atom? 7th grade

Chemistry
1 answer:
Gemiola [76]3 years ago
7 0

Answer:

it shows the breakdown of the atom

Explanation:

it will show it molecularly

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Krafla Volcano in Iceland,

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Is oxygen a beginning substance or ending substance?
stiks02 [169]

Answer:

Explanation:

The substances that are present at the beginning are called reactants and the substances present at the end are called products. Sometimes when reactants are put into a reaction vessel, a reaction will take place to produce products. Reactants are the starting materials, that is, whatever we have as our initial ingredients.Oxygen, a colorless, odorless, tasteless gas essential to living organisms, being taken up by animals, which convert it to carbon dioxide; plants, in turn, utilize carbon dioxide as a source of carbon and return the oxygen to the atmosphere. Oxygen forms compounds by reaction with practically any other element.

4 0
3 years ago
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Under what conditions does the hydrolysis of an amide bond occur?
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Hi.

I did some digging and I think I found what you're looking for.

I found this on Q(uizlet)

basic or acidic conditions and the reactants must be heated.

~
5 0
2 years ago
What minimum volume of 0.200 m potassium iodide solution is required to completely precipitate all of the lead in 155.0 ml of a
Blababa [14]
First, we write the balanced equation for this reaction:

2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂

From this equation, we see that there are 2 moles of potassium iodide required for each mole of lead (II) nitrate. Moreover, we may use the formula:

Moles = volume (in L) * molarity

We find the molar relation ship for KI : Pb(NO₃)₂ to be 2 : 1. So:

M₁V₁ = 2M₂V₂

V₁ = 2M₂V₂/M₁
V₁ = 2 * 0.112 * 0.155 / 0.2
V₁ = 0.1736 L


The volume required is 173.6 mL
5 0
3 years ago
You have an aqueous solution of chromium(III) nitrate that you titrate with an aqueous solution of sodium hydroxide. After a cer
barxatty [35]

Answer:

The precipitate was chromium hydroxide, which then reacted with more hydroxide to produce a soluble complex, Cr(OH)4

Explanation:

The following reaction takes place when chromium(III) nitrate reacts with NaOH:

Cr(NO)_{3} +3 NaOH → Cr(OH)_{3} (s)+ NaNO_{3}

The precipitate that is formed is chromium hydroxide, Cr(OH)_{3}

When more NaOH is added, the precipitate reacts with it which then results in the formation of a soluble complex ion:

Cr(OH)_{3}(s) + OH^{-}(aq) → Cr(OH)_{4} ^{-}(aq)

Cr(OH)_{4} ^{-} is soluble complex ion

7 0
3 years ago
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