this is monomial x polynomial, I need to write an expression with the picture above in simplest form.

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

Find the equation of the line perpendicular to y=3/2x-9 and passes through the point (6,2)

lys-0071 [83]

Answer:

y=-2/3x-2

Step-by-step explanation:

slope= -2/3

y=-2/3x+b

enter the given points

2=4+b

b=-2

y=-2/3x-2

6 0

3 years ago

Mariko needs about 18 wheelbarrows full of stone for her Japanese garden. Her wheelbarrow has vertical sides with the given shap

zlopas [31]

Answer:

I don't know yet haheuehehheejejejej

3 0

3 years ago

A local hamburger shop sold a combined total of 445 hamburgers and cheeseburgers on Tuesday. There were 55 fewer cheeseburgers s

liberstina [14]

Let x represent the number of hamburgers sold, and (x - 55) represent the number of cheeseburgers sold.

Set up an equation:
hamburgers + cheeseburgers = total number of burgers

x + (x-55) = 445

solve for x:
2x - 55 = 445

2x = 445 + 55

2x = 500

x = 500÷2

x = 250

This means 250 hamburgers were sold on Tuesday.

Hope this helps!

-Jabba

4 0

3 years ago

Please help me! i'm begging you

lions [1.4K]

The answer for this is B

5 0

3 years ago

Read 2 more answers

this is monomial x polynomial, I need to write an expression with the picture above in simplest form.​

this is monomial x polynomial, I need to write an expression with the picture above in simplest form.