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sergeinik [125]
2 years ago
7

this is monomial x polynomial, I need to write an expression with the picture above in simplest form.​

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
4 0

Answer:

2x(6x+1)

big rectangle - small rectangle = shaded region

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120 dollars is how many pounds
inna [77]
$120 USD is equivalent to £84.55
8 0
3 years ago
A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest
faltersainse [42]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396

add both amounts, and that's her investment for the 11 years.
7 0
3 years ago
An athlete plans to run 3 miles. each lap around the school yard is 3/7 mile. how many laps will the athlete run?
Maksim231197 [3]
He will need to run 7 laps.
8 0
3 years ago
The Ohio Department of Agriculture tested 203 fuel samples across the state in 1999 for accuracy of the reported octane level. F
OlgaM077 [116]

Answer:

The Sample size is 1918.89035

Step-by-step explanation:

Consider the provided information.

It is given that 14 out of 105 samples failed.

Therefore p = 14/105 = 0.13 3... and q=1-0.133=0.867

Samples would be needed to create a 99 percent confidence interval.

Subtract the confidence level from 1, then divide by two.

\frac{(1 -0.99)}{2}=0.005

By standard normal table z=2.5758≈2.58

Calculate the sample size as:

n=\frac{z^2pq}{e^2}

Where,  e is the margin of error,

Substitute the respective values.

n=\frac{(2.58)^2(0.133)(0.867)}{(0.02)^2}=1918.89

Hence, the Sample size is 1918.89035

4 0
2 years ago
50 POINTS!!! jamie will choose between two catering companies for an upcoming party. company A chargers a set-up fee of $500 plu
Shtirlitz [24]

Answer:

60 guests

Step-by-step explanation:

We'll say that the number of guests is n.

We're looking for the n where both of these expressions are equal:

Company A (500 set-up fee, 25 for each guest)

500 + 25 * n

Company B (200 set-up fee, 30 for each guest)

200 + 30 * n

500 + 25n = 200 + 30n

Subtract 200 from both sides.

300 + 25n = 30n

Subtract 25n from both sides.

300 = 5n

We'll reverse the sides.

5n = 300

Divide both sides by 5.

n = 300/5 = 60

Thus, both companies are equal when n is 60, or when there are 60 guests.

5 0
2 years ago
Read 2 more answers
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