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WINSTONCH [101]
3 years ago
10

A solid cylinder is radiating power. It has a length that is ten times its radius. It is cut into a number of smaller cylinders,

each of which has the same radius. Each small cylinder has the same temperature as the original cylinder. The total radiant power emitted by the pieces is twice that emitted by the original cylinder. How many smaller cylinders are there? Give your answer as a number with no units.
Physics
1 answer:
S_A_V [24]3 years ago
3 0

Answer:

The total number of small cylinder = 7.

Explanation:

Lets take

Radius of the large cylinder = R

length = L

L = 10 R

The total area A = 2 π R² + π R L

The length of the small cylinder = l

The number of small cylinder = n

L = n l

The total area of small cylinders

A'=n (2 π R² + π R l)

As we know that emissive power given as

P = A ε σ T⁴

For large cylinder

P = A ε σ T⁴      -----------1

For small cylinders

P'=A' ε σ T⁴    ------2

From 1 and 2

Given that

P'= 2 P

A' ε σ T⁴ =2 A ε σ T⁴

A'=2 A       (All others are constant)

n (2 π R² + π R l) =(2 2 π R² + π R L)

n (2  R² +  R l) = (2  R² +  R L)

n(2R^2+R\times \dfrac{L}{n}) = 2(2R^2+RL)

L = 10 R

n(2R^2+R\times \dfrac{10R}{n}) =2 (2R^2+R\times 10R)

n(2+\dfrac{10}{n}) =2( 2+ 10)

2 n +10 = 2 x 12

2 n +10 = 24

2 n = 24 -10

2 n = 14

n = 7

The total number of small cylinder = 7.

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approx. 0.43

Explanation:

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When an object of mass m1 is hung on a vertical spring and set into vertical simple harmonic motion, it oscillates at a frequenc
Arlecino [84]

Answer:

m_2/m_1=9.745

The ratio m_2/m_1 of the masses is 9.745

Explanation:

Formula for frequency when mass m_1 is hung on the spring:

f_1=\frac{1}{2\pi}\sqrt{\frac{k}{m_1}}

where:

k is the spring constant

Formula for frequency when mass m_2 is hung on the spring along with m_1:

f_2=\frac{1}{2\pi}\sqrt{\frac{k}{m_1+m_2}}

where:

k is the spring constant.

In order to find ratio m_2/m_1, Divide the above equations:

\frac{f_1}{f_2} =\frac{ \frac{1}{2\pi}\sqrt{\frac{k}{m_1}}}{\frac{1}{2\pi}\sqrt{\frac{k}{m_1+m_2}}}

On Solving the above equation:

\frac{f_1}{f_2} =\frac{\sqrt{\frac{k}{m_1}}}{\sqrt{\frac{k}{m_1+m_2}}}\\(\frac{f_1}{f_2})^{2} =\frac{m_1+m_2}{m_1} \\(\frac{11.8}{3.60})^2= \frac{m_1+m_2}{m_1} \\10.745=\frac{m_1+m_2}{m_1}\\10.745m_1=m_1+m_2\\m_2=10.745m_1-1m_1\\m_2/m_1=9.745

The ratio m_2/m_1 of the masses is 9.745

8 0
4 years ago
How do i get the correct answer for 0.429m to mm
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the answer for 0.429m to mm is 429

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3 years ago
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A mass of 0.4 kg hangs motionless from a vertical spring whose length is 0.95 m and whose unstretched length is 0.65 m. Next the
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Answer:

Explanation:

spring constant of spring = mg / x

= .4 x 9.8 / ( .95 - .65 )

=13.07 N / m

energy stored in spring = 1/2 k x²

= .5 x 13.07 x ( 1.2 - .65 )²

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Let it goes x m beyond its equilibrium position

Total energy at initial point

= 1.976 + 1/2 m v²

= 1.976 + .5 x .4 x 1.6²

= 2.488 J

energy at final point

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.4 x 9.8 x  ( .55 + x ) + .5 x 13.07 x² = 2.488

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6.535 x² + 3.92 x - .332 = 0

x = .075 m

7.5 cm

4 0
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