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3 years ago

You drop a rock down a well that is 11.5 m deep.How long does it take the rock to hit the bottom of the well ?

1 answer:

4 0

The acceleration of gravity depends on the distance from
the center of the Earth. We use 9.8 m/s² for any place that's
on the Earth's surface, or reasonably close. The 11.5 meters
down into the well certainly qualifies.

The formula we want is:

Distance of fall = (1/2) · (acceleration) · (time)²

      11.5 m = (1/2) (9.8 m/s²) (time)²

Divide each side
by 4.9 m/s² : (11.5m) / (4.9 m/s²) = time²

   2.347 sec² = time²

   time = √(2.347 sec²) =   1.53 seconds .

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Answer:

Given the area A of a flat surface and the magnetic flux through the surface $\Phi$ it is possible to calculate the magnitude $\frac{\Phi}{A}=B\ cos \theta$ .

Explanation:

The magnetic flux gives an idea of how many magnetic field lines are passing through a surface. The SI unit of the magnetic flux $\Phi$ is the weber (Wb), of the magnetic field B is the tesla (T) and of the area A is ( $m^{2}$ ). So 1 Wb=1 T.m².

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$\Phi=B\ A\ cos\theta$

We are told the values of $\Phi$ and B, then we can calculate the magnitude

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2 years ago

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3 years ago

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What are the answers please help

aleksandr82 [10.1K]

Answer:

a.) The main scale reading is 10.2cm

b.) Division 7 = 0.07

c.) 10.27 cm

d.) 10.31 cm

e.) 10.24 cm

Explanation:

The figure depicts a vernier caliper readings

a.) The main scale reading is 10.2 cm

The reading before the vernier scale

b.) Division 7 = 0.07

the point where the main scale and vernier scale meet

c.) The observed readings is

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correct reading = 10.27 + 0.04 = 10.31cm

e.) If the instrument has a negative zero error of 3 division

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2 years ago

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Answer:

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