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3 years ago

If s car can drive 40m/s, then how long will it take to travel 2400m?

Physics

2 answers:

WINSTONCH [101]3 years ago

8 0

Answer:

60 seconds.

Explanation:

2400 divided by 40 equals 60

dimaraw [331]3 years ago

3 0

Answer:

One minute

Explanation:

2400/40

=60

60 secs. = 1 min.

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Ionic compounds have high melting points because a lot of energy is needed to break the bonds between the ions.

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Read 2 more answers

Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the

Over [174]

Answer:

Part a)

$a= 0.32 m/s^2$

Part b)

$F_c = 3.6 N$

Part c)

$F_c = 5.5 N$

Explanation:

Part a)

As we know that the friction force on two boxes is given as

$F_f = \mu m_a g + \mu m_b g$

$F_f = 0.02(10.6 + 7)9.81$

$F_f = 3.45 N$

Now we know by Newton's II law

$F_{net} = ma$

so we have

$F_p - F_f = (m_a + m_b) a$

$9.1 - 3.45 = (10.6 + 7) a$

$a = \frac{5.65}{17.6}$

$a= 0.32 m/s^2$

Part b)

For block B we know that net force on it will push it forward with same acceleration so we have

$F_c - F_f = m_b a$

$F_c = \mu m_b g + m_b a$

$F_c = 0.02(7)(9.8) + 7(0.32)$

$F_c = 3.6 N$

Part c)

If Alex push from other side then also the acceleration will be same

So for box B we can say that Net force is given as

$F_p - F_f - F_c = m_b a$

$9.1 - 0.02(7)(9.8) - F_c = 7(0.32)$

$F_c = 9.1 - 0.02 (7)(9.8) - 7(0.32)$

$F_c = 5.5 N$

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3 years ago

How many times longer than the length of one year is the age of the universe?

Len [333]

No one can really tell exactly how old the universe is. However, scientists have attempted to estimate the time by using the concept of Doppler effect which depends on the frequency of the stars and their relative velocities. From literature, the universe is about 13.82 billion years old. Thus, the age of the universe is 13.82×10⁹ times longer than a year.

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3 years ago

The chart show the masses and velocities of two colliding objects that stick together after a collision.

finlep [7]

Answer:

1,500 kg.m/s

Explanation:

First, arrange the information in a table:

Object Mass (kg) Velocity (m/s)

A 200 15

B 150 - 10

After the collision, the two objects are stick together, thus you talk aobut one object and one momentum.

According to the law of convervation of momentum, the momentum after the collision is equal to the momentum before the collision.

Momentum before the collision, P₁:

$P_1=m_{A,1}\times v_{A,1}+m_{B,1}\times v_{B,1}$

$P_1=200kg\times 15m/s+150kg\times (-10m/s)\\\\ P_1=3000kg.m/s-1500kg.m/s=1500kg.m/s$

Momentum after the collision:

As stated, it es equal to the momentum before the collision: 1,500 kg . m/s

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3 years ago