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user100 [1]
3 years ago
6

Mason plans to use a strategy to find the product of 32 * 250. Write a strategy Mason could use to find the product.

Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0
This could be a strategy: 8 × 3 ×250.
krek1111 [17]3 years ago
5 0
8x4x125x2 . 8x4 would give you 32 and 125x2 would give you 250.
You might be interested in
Please help meee! im confused!
kherson [118]

f(x)=y=√x looks something like this:

(4,2)

(9,3)

(16,4)

Whilst your graph is much higher slope, for lack of better term

Rules of transformation

f(x)+b - function is shifted b units upward (up y-axis)

f(x)-b - function is shifted b units downward (down y-axis)

f(x+b) - function is shifted b units to the left (negative x-axis)

f(x-b) - function is shifted b units to the right (positive x-axis)

-f(x) - function is reflected over x-axis

f(-x) - function is reflected over y-axis

bf(x) - vertical stretch for |b| > 1, vertical shrink for 0< |b| <1

f(bx) - horizontal shrink for |b| > 1, horizontal stretch for 0< |b| <1
**INVALIDATE my answer, as statements were given 10 mins after posted**

8 0
2 years ago
Read 2 more answers
Plz help I'll give brainlest
jarptica [38.1K]
<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 m^2</h3><h3>3.Area of the trapezoid   = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is  = 1200 square in</h3><h3>8.The area of the rhombus is =84 cm^2</h3><h3>9.Area of the trapezoid  = 240 square ft</h3>

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

                                        =(9×5) m^2

                                         =45 m^2

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                            =\frac{1}{2} \times (12+5) \times 4 square in.

                             = 34 square in.

4.

Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                              =\frac{1}{2} \times (2+6) \times 2 square ft

                              = 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 6\times 9 square cm

                               = 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 12\times 18 square in

                               = 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

                                            = 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = \frac {1}{2} \times 14 \times 12 cm^2

                                         =84 cm^2

9.Given , the base of trapezoid are 24 ft  and 16 ft and height is 12 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                                    = \frac{1}{2} \times (24+16) \times 12 square ft

                                     = 240 square ft

8 0
3 years ago
the figure is made up of a semicircle and a triangle. Find the area of the figure. Use pi equals 3.14​
valentinak56 [21]

Answer:

The area of the figure is 63.25 square feet

Step-by-step explanation:

we know that

The area of the figure is equal to the area of semicircle plus the area of triangle

step 1

Find the area of semicircle

The area of semicircle is

A_1=\frac{1}{2}\pi r^{2}

we have

r=10/2=5\ ft ----> the radius is half the diameter

\pi =3.14

substitute

A_1=\frac{1}{2}(3.14)5^{2}

A_1=39.25\ ft^2

step 2

Find the area of the triangle

The area of triangle is equal to

A_2=\frac{1}{2}bh

we have

b=8\ ft\\h=6\ ft

substitute

A_2=\frac{1}{2}(8)(6)

A_2=24\ ft^2

step 3

The area of the figure is equal to

A=A_1+A_2

substitute

A=39.25+24=63.25\ ft^2

5 0
4 years ago
Every week at the Cougar Scouts meeting, Diane is in charge of the craft activity. This week, she decides to make pinecone bird
liraira [26]

Answer:

I AM NOT ABLE TO GIVE THE ANSWER OF THIS QUESTION

3 0
3 years ago
Can someone please help me .
dusya [7]

Answer:

for 10. a

for 11. f.

Step-by-step explanation:

5 0
3 years ago
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