All categories

3 years ago

Mason plans to use a strategy to find the product of 32 * 250. Write a strategy Mason could use to find the product.

Mathematics

2 answers:

DIA [1.3K]3 years ago

8 0

This could be a strategy: 8 × 3 ×250.

krek1111 [17]3 years ago

5 0

8x4x125x2 . 8x4 would give you 32 and 125x2 would give you 250.

You might be interested in

Write 0.0000000068 as a scientific notation

Y_Kistochka [10]

Answer:

10×6.8 to the 9th power

3 0

3 years ago

What is the solution to the inequality? 10x + 18 < -2

padilas [110]

Let's solve your inequality step-by-step.

10x+18<−2

Step 1: Subtract 18 from both sides.

10x+18−18<−2−18

10x<−20

Step 2: Divide both sides by 10.

10x/10<−20/10

x<−2

Answer:

x<−2

4 0

3 years ago

Can someone help me please?

Elena-2011 [213]

<h3>Answer: 4368 square feet</h3>

======================================================

Explanation:

Check out the diagram below

I drew a rectangle with dimensions 56 ft by 78 ft.

Then I broke up the 56 into 50+6, and I broke up the 78 into 70+8

The reason for this is because it's fairly easy to multiply the areas of each smaller rectangle at this point

In the upper left corner, we have an area of 50*70 = 3500. Note how this is basically 5*7 = 35, but we tack on the two zeros (from 50 and 70 combined)
In the upper right corner, we have an area of 70*6 = 420
In the lower left corner, we have an area of 50*8 = 400
In the lower right corner, we have an area of 6*8 = 48

Add up all the areas found: 3500+420+400+48 = 4368

As a way to check, using your calculator shows that 56*78 = 4368

8 0

2 years ago

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

Alla [95]

Answer: mass (m) = 4 kg

center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

Points (0,0) and (2,1):

y = $\frac{1-0}{2-0}(x-0)$

y = $\frac{x}{2}$

Points (2,1) and (0,3):

y = $\frac{3-1}{0-2}(x-0) + 3$

y = -x + 3

Now, find total mass, which is given by the formula:

$m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }$

Calculating for the limits above:

$m = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2(x+y)} \, dy \, dx }$

where a = -x+3

$m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {(xy+\frac{y^{2}}{2} )} \, dx }$

$m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx }$

$m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx }$

$m = 2.(\frac{-3.2^{2}}{2}+3.2-0)$

m = 2(-4+6)

m = 4

Mass of the lamina that occupies region D is 4.

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$