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2 years ago

What is the distance between (5, 7) and (-2,-2)? Round to the nearest tenth, if necessary.

Mathematics

1 answer:

lakkis [162]2 years ago

5 0

Answer:

The distance between (5, 7) and (-2,-2) is 11.4 units.

Step-by-step explanation:

We are given the following in the question:

Points:

(5, 7) and (-2,-2)

We have to find the distance between the two points.

Distance formula:

$d =\sqrt{(y_2-y_1)^2+(x_2-x_1)^2)}$

Putting values, we get,

$(x_1,y_1) = (5,7)\\(x_2,y_2) = (-2,-2)\\\\d = \sqrt{(-2-7)^2 + (-2-5)^2} = \sqrt{130} \approx 11.4\text{ units}$

Thus, the distance between (5, 7) and (-2,-2) is 11.4 units.

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Suppose you are conducting a survey about the amount grocery store baggers are tipped for helping customers to their cars .for a

ELEN [110]

Using the Empirical Rule and the Central Limit Theorem, we have that:

About 68% of the sample mean fall with in the intervals $1.64 and $1.82.

About 99.7% of the sample mean fall with in the intervals $1.46 and $2.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

<h3>What does the Central Limit Theorem state?</h3>

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem, the standard deviation of the distribution of sample means is:

$s = \frac{0.657}{\sqrt{50}} = 0.09$

68% of the means are within 1 standard deviation of the mean, hence the bounds are:

1.73 - 0.09 = $1.64.

1.73 + 0.09 = $1.82.

99.7% of the means are within 3 standard deviations of the mean, hence the bounds are:

1.73 - 3 x 0.09 = $1.46.

1.73 + 3 x 0.09 = $2.

More can be learned about the Empirical Rule at brainly.com/question/24537145

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5 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> What is the value of x?

MA_775_DIABLO [31]

Answer: $\bold{C)\ -\dfrac{1}{2}}$

<u>Step-by-step explanation:</u>

$.\qquad \dfrac{x+2}{15}=\dfrac{x+1}{5}\\\\\\\rightarrow (15)\dfrac{x+2}{15}=\dfrac{x+1}{5}(15)\\\\\\\rightarrow x+2=3(x+1)\\\\\rightarrow x+2=3x+3\\\\\rightarrow \qquad 2=2x+3\\\\\rightarrow \qquad -1=2x\\\\\rightarrow \qquad -\dfrac{1}{2}=x$

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3 years ago

If two standard six-sided dice are tossed, what is the probability that a 5 is rolled on at least one of the two dice? express y

zaharov [31]

We define the probability of a particular event occurring as:
$\frac{number\ of \ desired\ outcomes}{number\ of\ possible\ outcomes}$

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.

Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:

(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5

So, we have $\frac{3}{36} = \frac{1}{12}$ probability of rolling at least one 5.