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lianna [129]
4 years ago
12

8xq the product is between 0 and 8 when q equals 5/3 because 5/3 is greater than 1 and less than 2 true or false

Mathematics
1 answer:
Tomtit [17]4 years ago
5 0
False. The answer should be between 8 and 16 because 5/3 = 1 2/3 which is between 1 & 2

So the product is between. 1 x 8 and 2 x 8
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Paul is saving for a down payment to buy a house. The account earns 13% interest compound quarterly, and he wants to have $15,00
Tatiana [17]

Answer:

The principal must be = $8991.88

Step-by-step explanation:

Formula for compound interest is:

A = P(1 + \frac{r}{n})^{nt}

Where A is the amount after 't' years.

P is the principal amount

n is the number of times interest is compounded each year.

r is the rate of interest.

Here, we are given that:

Amount, A = $15000

Rate of interest = 13 % compounded quarterly i.e. 4 times every year

Number of times, interest is compounded each year, n = 4

Time, t = 4 years.

To find, Principal P = ?

Putting all the given values in the formula to find P.

15000 = P(1 + \frac{13}{400})^{4\times 4}\\\Rightarrow 15000 = P(1 + 0.0325)^{16}\\\Rightarrow 15000 = P(1.0325)^{16} \\\Rightarrow 15000 = P \times 1.66817253\\\Rightarrow P = \dfrac{15000}{1.66817253}\\\Rightarrow P \approx \$8991.88

So, <em>the principal must be = $8991.88</em>

4 0
3 years ago
If x/3= x+1/4, What is the value of x
olya-2409 [2.1K]
Well first because in this equation the first value is less than one, we should multiply the whole equation by 3, so
<span>x/3= x+1/4
x=3x+3/4
now we should switch the values
3x+3/4=x
now subtract x from both sides
2x+3/4=0
now subtract 3/4 from both sides
2x=-3/4
now divide both sides by 2
x=3/8
So that's your answer!

</span>
8 0
3 years ago
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vlabodo [156]

Answer:

x(x^2+2)^3/2

Step-by-step explanation:

y'=1/2(x^2+2)^3/2.2x

= x(x^2+2)^3/2

8 0
2 years ago
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1. n + 5
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3. 8 - x
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3 0
4 years ago
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You put names of all the students in your class in a paper bag.there are 14 boys and 20 girls .if you draw a name at random, wha
I am Lyosha [343]
14/34 could be your answer 


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