X - the number of plants in 8 in pots
y - the number of plants in 10 in pots
4 plants in 8 in pots and 2 in 10 in pots.
It’ll be D) 7/46 you can reduce it by dividing everything with 4
Answer:
x = 8 and y = 10
Step-by-step explanation:
Since the figures are congruent:
Angle PQR = EFG
6y + x = 68
Segment QR = FG
2x - 4 = 12
Solving that:
2x - 4 = 12
2x = 16
x = 8
Replacing x in 6y + x =68
6y + 8 = 68
6y = 60
y = 10
Answer:
The correct answer is C, as growth on stock E is bigger from the growth of stock B
Step-by-step explanation:
In order to resolve this problem, we must have in mind that the negative numbers are smaller when they are more distant from 0, and that positive numbers are bigger when they are more distant from 0. So, the biggest number of growth is the one that is more distant from 0.
The correct answer is C, as growth on stock E is bigger from the growth of stock B.
If EF = 6 and EG=21 find the value of FG. The answer is 15.
