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3 years ago

Need help with a functions problem. I have attached a photo of the problem. Thanks a lot.

Mathematics

1 answer:

Lesechka [4]3 years ago

7 0

A) (-6,-3], (-3, 3), [3,7)

B) (-5,-5), (-3,-3), (-1,6)

C)6

D) X=5

E) f(2)= -3

F)4 & 6

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What's the probability you will flip 3 coins in a row and they all land on HEADS?

liberstina [14]

Answer:

B. 1/8 chance

Step-by-step explanation:

Every time you flip a coin you have a 1/2 probability of landing on heads.

If you repeated the process three times in the row

It would be 1/2 x 1/2 x 1/2 = 1/8

The odds they all land on heads is 1/8

6 0

3 years ago

write an expression that is equivalent to -24 - 52 .(this is my question: what do i do for the sentence above? And please show m

Blababa [14]

I think that it is simply asking to rewrite. So this would simplify to -76. But the expression -52-24 is also -76

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3 years ago

Consider a game in which you flip a coin. If it comes up heads, you earn 1 point; if it comes up tails, you earn 0 points. What

Sergeeva-Olga [200]

Answer:

C. 0.5

Step-by-step explanation:

Since a coin has 2 sides and there is the same probability of getting either side, then each side has a 50% or 0.5 probability. Therefore, in order to calculate the expected value of one coin flip we need to multiply the value of each side by its probability and add those values together like so...

1 * 0.5 = 0.5

0 * 0.5 = 0

Now we add these values together...

0.5 + 0 = 0.5

Finally, we can see that the expected value of one coin flip is 0.5

4 0

3 years ago

Use separation of variables to solve dy dx − tan x = y2 tan x with y(0) = √3. Find the value of c in radians, not degrees

a_sh-v [17]

Answer:

$y(x)=tan(-log(cos(x))+\frac{\pi }{3} )$

Step-by-step explanation:

Rewrite the equation as:

$\frac{dy(x)}{dx}-tan(x)=y(x)^{2} *tan(x)$

Isolating $\frac{dy}{dx}$

$\frac{dy}{dx} =tan(x)+tan(x)*y^{2}$

Factor:

$\frac{dy}{dx} =tan(x)*(1+y^{2} )$

Dividing both sides by $(1+y^{2} )$ and multiplying them by $dx$

$\frac{dy}{1+y^{2} } =tan(x)dx$

Integrate both sides:

$\int\ \frac{dy}{1+y^{2} } = \int\ tan(x) dx$

Evaluate the integrals:

$arctan(y)=-log(cos(x))+C_1$

Solving for y:

$y(x)=tan(-log(cos(x))+C_1)$

Evaluating the initial condition:

$y(0)=\sqrt{3} =tan(-log(cos(0))+C_1)=tan(-log(1)+C_1)=tan(0+C_1)$

$\sqrt{3} =tan(C_1)\\arctan(\sqrt{3} )=C_1\\60=C_1$

Converting 60 degrees to radians:

$60degrees*\frac{\pi }{180degrees} =\frac{\pi }{3}$

Replacing $C_1$ in the diferential equation solution:

$y(x)=tan(-log(cos(x))+\frac{\pi }{3} )$

3 0

3 years ago

Help please; I need the right answer

Ad libitum [116K]

Answer:

Step-by-step explanation:

$\cos x+\sqrt{2}=-\cos x \\ 2\cos x = -\sqrt 2 \\ \cos x = -\dfrac{\sqrt 2}{2}\\ \\ \Rightarrow x = \pm \arccos\Big(-\dfrac{\sqrt 2}{2}\Big)+2k\pi,\quad x\in \mathbb{Z}\\ \Rightarrow x =\pm\dfrac{3\pi}{4}+2k\pi\\ \\ \\k = -1 \Rightarrow x < 0\\\\ k=0 \Rightarrow x 2\pi$

3 0

4 years ago

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