Answer:
Since the values vary from 0.5 to 4.5, let's take 5 intervals of width 1 unit each
(Lower boundary is included, upper boundary is not)
Average
no. of --------> frequency
movies
_______ __________
0 - 1 --------------> 1
1 - 2 --------------> 5
2 - 3 --------------> 5
3 - 4 --------------> 2
4 - 5 --------------> 1
For frequencies, just count the data values in each interval
Answer:its 20400
Step-by-step explanation:
Answer:
x=8
Step-by-step explanation:
8-2=6
8x7=42
(checked)
She has 47 total
20 are from Europe
some are from Africa,
and some from Asia
how many from Africa? hmm let's say "a"
how many from Asia? hmm let's say "b"
we know that, she has twice as many "a" as she has "b" stamps,
so, whatever "b" is, a = 2 * b, or a = 2b
so.. let us add them together

solve for "b", to see how many from Asia she has
what's "a"? well, a = 2b , that's how many African ones she has :)
Answer:
Step-by-step explanation:
You multiply 14.1 times 14.1 and you get 198.81 which is the closest to 200