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Neporo4naja [7]
2 years ago
15

Are x and y proportional?

Mathematics
1 answer:
Vesna [10]2 years ago
4 0

Answer:

yes, or try no if you have enough guesses

Step-by-step explanation:

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I have attached the question for you
scoundrel [369]

Answer:

s = \frac{1}{3}

Step-by-step explanation:

s = ut + \frac{1}{2} at² ( substitute the given values into the equation )

s = ( 3 × \frac{1}{3} ) + ( \frac{1}{2} × - 12 × (\frac{1}{3} )² )

  = 1 + (- 6 × \frac{1}{9} )

  = 1 + ( - \frac{2}{3} )

  = 1 - \frac{2}{3}

  = \frac{1}{3}

4 0
2 years ago
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Solve the given system of equations by Elimination.<br> x + y = 6<br> 3x - y = 14
olganol [36]

Answer:

Step-by-step explanation:

8 0
3 years ago
Plz help me it urgent
kykrilka [37]

Answer:

12/(3/4) = 12x4/3 = 16 counters

Step-by-step explanation:

so your answer is 16 counter i redid the math and Nonsibi helped me see where I went wrong sorry

4 0
3 years ago
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A cherry farm estimates from past records that if 23 trees are planted per​ acre, each tree will yield an average of 55 pounds o
Ivenika [448]

Answer:

  39

Step-by-step explanation:

Yield goes down 1 lb for each tree over 23 per acre, so the yield per tree as a function of x trees per acre is ...

  yield per tree = 55 -(x -23) = 78 -x . . . . . pounds of cherries

To get the yield per acre, we multiply the number of trees per acre by the yield per tree:

  lb/acre = (x tree/acre)((78 -x) lb/tree) = x(78 -x)

This is a quadratic function that opens downward and has zeros at x=0 and x=78. The vertex (maximum) is on the line of symmetry, halfway between the zeros. The yield per acre will be a maximum when ...

  x = (0 +78)/2 = 39 . . . . trees per acre

39 trees should be planted per acre to maximize yield per acre.

3 0
2 years ago
Kayla mixes 1/6 pound of salt with 1/8 bucket of water to make a saline solution. How much salt does she need to use for a full
Debora [2.8K]

ANSWER

4/3 pounds of salt

EXPLANATION

We are given that Kayla mixes 1/6 pound of salt with 1/8 bucket of water to make a saline solution.

We want to find out how much salt she will need to mix with a bucket of water.

To do this, we will compare and cross multiply,

That is, let the amount of salt needed be x:

\begin{gathered} \frac{1}{6}\text{ pound of salt = }\frac{1}{8}\text{ bucket of water} \\ \Rightarrow\text{x pound of salt = }1\text{ bucket of water} \\ \text{Cross-multiply:} \\ 1\cdot\text{ }\frac{1}{6}\text{ = x }\cdot\text{ }\frac{1}{8} \\ \Rightarrow\text{ x = }\frac{8\cdot\text{ 1}}{6}\text{ = }\frac{8}{6} \\ \Rightarrow\text{ x = }\frac{4}{3}\text{ pounds of salt or 1}\frac{1}{3}\text{ pounds of salt} \end{gathered}

Kayla will need 4/3 pounds of salt or 1 1/3 pounds of salt

8 0
1 year ago
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