Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;
then;
or
miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles
x=8+sqrt-8/12, x=8-sqrt-8/12
I think...
Answer:
1.
%K = 31.904%
%Cl = 28.930%
%O = 39.166%
2.
Hg = 80.69/ 200.59 = 0.40/0.2 = 2
S = 6.436/ 32.07 = 0.20/0.2 = 1
O = 12.87/ 16.00 = 0.80/0.2 = 4
Hg2SO4 is the empirical formula
Step-by-step explanation:
Answer:
t as a function of height h is t = √600 - h/16
The time to reach a height of 50 feet is 5.86 minutes
Step-by-step explanation:
Function for height is h(t) = 600 - 16t²
where t = time lapsed in seconds after an object is dropped from height of 600 feet
t as a function of height h
replacing the function with variable h
h = 600 - 16t²
Solving for t
Subtracting 600 from both side
h - 600 = -16t²
Divide through by -16
600 - h/ 16 = t²
Take square root of both sides
√600 - h/16 = t
Therefore, t = √600 - h/16
Time to reach height 50 feet
t = √600 - h/16
substituting h = 50 in the equation
t = √600 - 50/16
t = √550/16
t= 34.375
t = 5.86 minutes
