Look at the attachment
1 answer:
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Answer:
32,292,000
Step-by-step explanation:
In your question, it asks how many license plate combinations we could make WITHOUT repeats.
We need some prior knowledge to answer this question.
We know that:
- There are 26 letters in the alphabet
- We can make 10 digits (0 - 9)
With the information we know above, we can solve the question.
Since we CAN'T have repeats, we would be excluding a letter or number for each license plate.
We're going to need to multiply each "section" in order to find how many combinations of license plates we can make.
We decrease by one letter and one number in each section since we can't have repeats.
Now, we can solve.
Work:
When you're done multiplying, you should get 32,292,000.
This means that there could be 32,292,000 different combinations of license plates.
<h3>I hope this helps you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>Answer:
13
Step-by-step explanation:
First, fill in 3 boxes of the table using the given information (blue numbers on the attached table)
"Of the 32 students that have a cell phone, 19 students do not have a tablet."
The top row of the table is students who have a cell phone. Therefore, place 19 in the box in this row that is in the "no tablet" column.
"Of the 70 students that have a tablet, 57 students do not have a cell phone."
The first column of the table is students who have a tablet. Therefore, place 57 in the box in the 2nd row of this column.
"11 students do not have a cell phone or a tablet."
Find the "no cell phone" row and the "no tablet" column and place 11 in the box that coincides.
We can calculate the blank totals using addition (shown by green numbers on the attached table)
- Total students with no cell phone = 57 + 11 = 68
- Total students with no tablet = 19 + 11 = 30
To calculate the number of students who have a cell phone AND a tablet:
⇒ Total students with a cell phone <em>minus</em> students with a cell phone but no tablet
⇒ 32 - 19 = 13
