Solve the following system using either linear combination or substitution. Round any answers to the hundredths place. Show all
1 answer:
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For this case we must find the solution of the following quadratic equation:
Where:
Then, the solution is given by:
Substituting the values:
By definition we have:
Thus, we have two complex roots.
Answer:
The equation has no real roots.
Answer:
44 units
Step-by-step explanation:
Since B is the mid-point of AC
AB=BC
or,4x+14=x+20
or, 4x-x=20-14
or 3x=6
or,x=6/3=2
AC=AB+BC
= 4x+14+x+20
= 4(2) + 14 +2 +20
= 8+14+22
=44 units
