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GalinKa [24]
3 years ago
8

Solve the following system using either linear combination or substitution. Round any answers to the hundredths place. Show all

work
x-10y=6
y=-5x-23
Mathematics
1 answer:
12345 [234]3 years ago
3 0
So if y=-5x-23 then we can plug that value in for y in x-10y=6, so it becomes

x-10(-5x-23)=6

x+50x+230=6

51x=-224

x=-4.39

plug this x value into the equation y=-5x-23

y=-5(-4.39)-23

y=21.95-23

y=-1.05
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How to write 4(x-8) in verbal expression
Trava [24]
4 times x minus 8 is the answer
7 0
3 years ago
construct a 90% confidence interval of the population proportion using the giver information x=74 n=150
FrozenT [24]

Answer:

The 90% confidence interval of the population proportion is (0.43, 0.56).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

The information provided is:

<em>X</em> = 74

<em>n</em> = 150

Confidence level = 90%

Compute the value of sample proportion as follows:

\hat p=\frac{X}{n}=\frac{74}{150}=0.493

Compute the critical value of <em>z</em> for 90% confidence level as follows:

z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645

*Use a <em>z</em>-table.

Compute the 90% confidence interval of the population proportion as follows:

CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.493\pm 1.645\times \sqrt{\frac{0.493(1-0.493)}{150}}\\\\=0.493\pm 0.0672\\\\=(0.4258,\ 0.5602)\\\\\approx (0.43,\ 0.56)

Thus, the 90% confidence interval of the population proportion is (0.43, 0.56).

3 0
3 years ago
10 POINTS!!!
WINSTONCH [101]

Answer:

2x^3 + 6x^2

Step-by-step explanation:

Volumen = area * height

You already had the area which is:

x^2 + 3x

and the heigth is 2x

Volumen = (x^2 + 3x)* 2x

Volumen = 2x^3 + 6x^2

3 0
3 years ago
Read 2 more answers
If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK
Gala2k [10]

Answer:

The value of mHLK will be "(204)°".

Step-by-step explanation:

The given values are:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

mHLK = ?

Now,

By using chord-chord formula of angle, we get

mHMK=\frac{1}{2}(mJL+mHLK)

On putting the values in the above formula, we get

⇒  (8x-1)=\frac{1}{2}(15x-36+3x+2)

On applying cross-multiplication, we get

⇒  2(8x-1)=18x-34

⇒  16x-2=18x-34

On subtracting "18x" from both sides, we get

⇒  16x-2-18x=18x-34-18x

⇒  -2x-2=-34

On adding "2" both sides, we get

⇒  -2x=-34+2

⇒  -2x=-32

⇒  x=\frac{32}{2}

⇒  x=16

On putting the value of "x" in mHLK = (15x-36)°, we get

⇒ (15x-36)° = (15×16-36)°

⇒                = (240-36)°

⇒                = (204)°

So that mHLK = (204)°

4 0
3 years ago
ABC with vertices A(-3,0) B(-2,3) C(-1,1) is rotates 180 clockwise about the origin. If it is then reflected across y=-x
bazaltina [42]
A(0,-3) B(3,-2) and C(1,-1)
5 0
3 years ago
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