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2 years ago

Helppppopppppppppppppphsbdbfhfevd

Mathematics

2 answers:

MaRussiya [10]2 years ago

7 0

Answer: i think its A but i may be wrong

Step-by-step explanation: hope its right and hope this helps

sdas [7]2 years ago

4 0

Answer:

Step-by-step explanation:

because it says in your thing up above to exchange but there is a 50% im wrong

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Find the limit of the function algebraically. limit as x approaches negative nine of quantity x squared minus eighty one divided

scoray [572]

Let me express the equation clearly:

lim x→-9 (x²-81)/(x+9)

Initially, we solve this by substituting x=-9 to the equation.

((-9)²-81)/(-9+9) = 0/0

The term 0/0 is undefined. This means that the solution is not see on the number line because it is imaginary. Other undefined terms are N/0 (where N is any number), 0⁰, 0×∞, ∞-∞, 1^∞ and ∞/∞. One way to solve this is by applying L'Hopitals Rule. This can be done by differentiating the numerator and denominator of the fraction independently. Then, you can already substitute the x=-9.

(2x-0)/(1+0) = 2x = 2(-9) = -18

The other easy way is to substitute x=-8.999 to the original equation. Note that the term x→-9 means that x only approaches to -9. Thus, you substitute a number that is very close to -9. Substituting x=-8.999

((-8.999)²-81)/(-8.999+9) = -18

7 0

3 years ago

A chef plans to mix 100% vinegar with Italian Dressing. The Italian dressing contains 8% vinegar. The chef wants to make 60 mill

GenaCL600 [577]

Answer:

Let v = ml of 100% vinegar

Then 150-v = ml of dressing

v + .05(150-v) = .24(150)

v + 7.5 - .05v = 36

.95v = 28.5

v = 28.5/.95

v = 30 ml of vinegar

dressing = 150-30 = 120 m

5 0

2 years ago

7 added to the product of 14 and f

Doss [256]

14f + 7

“Product” means multiplication, so we can assume 14 and f are being multiplied (14f.) Add that to 7, and you have an expression! Have a great day.

4 0

2 years ago

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, should the signs in the binom

gtnhenbr [62]

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, the signs in the binomials should be both positive

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the true statement?</h3>

The form of the polynomial is given as:

ax2 + bx + c

Where a, b, and c are positive real numbers.

Since a, b, and c are positive real numbers. then the form of the expansion would be:

ax2 + bx + c = (dx + e)(fx + g)

<h3>Example to verify the claim</h3>

Take for instance, we have the following quadratic equation

x^2 + 6x + 8

Expand the equation

x^2 + 6x + 8 = x^2 + 4x + 2x + 8

Factorize the equation

x^2 + 6x + 8 = (x + 2)(x + 4)

Hence, the signs in the binomials should be both positive

Helppppopppppppppppppphsbdbfhfevd​

Helppppopppppppppppppphsbdbfhfevd