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miv72 [106K]
3 years ago
10

What are the highest perfect square multiples of 175

Mathematics
1 answer:
avanturin [10]3 years ago
5 0
The highest multiple are 5 and 35
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so far , a storm has traveled 35 miles in 1/2 hour. if its currently 5:00pm and the storm is 105 miles away from you , at what t
SVETLANKA909090 [29]

Answer:

hey do you want money if yes then tell me I will give you 1000$

6 0
3 years ago
A cylinder has a base diameter of 20 meters and a height of 10 meters. What is it’s volume in cubic meters, to the nearest tenth
Korvikt [17]

3141.6 cubic meters

Step-by-step explanation:

The volume of a cylinder is given by;

πr²h

π * (²⁰/₂)² * 10

π * 100 * 10

= 3141.6

4 0
3 years ago
One spinner has three equally sized sectors numbered 1, 2, and 3. A second spinner has two equally sized sectors labeled Top (T)
SSSSS [86.1K]
I would say, well, if there are 3 sides that are equal on spinner 1. They are equal. But, we are focusing on spinner two that has two sides. If there is only 2 equal sides then, they would have to be straight across from each other. So that is 180. 360 is full circle. take away 180 to get answer. 
360-180=180
I hope this helped. And sorry if it is not the correct answer. But that is how I would of answered it
4 0
3 years ago
Read 2 more answers
In ΔLMN, \overline{LN}
Karolina [17]

Answer:

\bold{\angle NLM = 10^\circ}

Step-by-step explanation:

Given a ΔLMN.

Line LN is extended to point O.

such that:

\text{m}\angle MNO = (5x-13)^{\circ}

\text{m}\angle NLM = (x-4)^{\circ} and

\text{m}\angle LMN = (2x+19)^{\circ}

To find:

\text{m}\angle NLM=?

Solution:

Kindly refer to the attached image for the given triangle and dimensions of angles.

Let us recall the external angle property of a triangle:

The external angle of a triangle is equal to the sum of two opposite internal angles.

i.e.

\angle MNO = \angle NLM + \angle LMN\\\Rightarrow 5x-13 = x-4+2x+19\\\Rightarrow 5x-13 = 3x+15\\\Rightarrow 5x-3x = 13+15\\\Rightarrow 2x=28\\\Rightarrow x =14

Putting the value of x in \angle NLM.

\angle NLM=14-4 \\\Rightarrow \bold{\angle NLM = 10^\circ}

5 0
3 years ago
Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

6 0
3 years ago
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