What are the highest perfect square multiples of 175

fair coin is tossed three times. What is the probability that all three tosses land on heads,given that:(a) the first toss lands

maxonik [38]

Answer:

(a) The probability that all three tosses land on heads given that the 1st toss lands on Heads is $\frac{1}{4}$ .

(b) The probability that all three tosses land on heads given that at least one toss lands on heads is $\frac{1}{7}$ .

Step-by-step explanation:

The sample space of tossing 3 coins is:

S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} = 8 outcomes.

(a)

The sample space such that the 1st toss lands on Heads is:

S₁ = {HHH, HHT, HTH, HTT} = 4 outcomes.

The probability that all three tosses land on heads given that the 1st toss lands on Heads is:

P (3 Heads | 1st toss is Heads) = $\frac{P(3\ Heads\ \cap \ 1st\ toss\ is\ Heads)}{P(1st\ toss\ is\ Heads)}$

$=\frac{\frac{1}{4} }{\frac{4}{8} } \\=\frac{1}{8}\times \frac{8}{4}\\ =\frac{1}{4}$

Thus, the probability that all three tosses land on heads given that the 1st toss lands on Heads is $\frac{1}{4}$ .

(b)

The sample space such that at least one toss lands on heads is:

S₂ = {HHH, HHT, HTH, THH, HTT, THT, TTH} = 7 outcomes

The probability that all three tosses land on heads given that at least one toss lands on heads is,

P (3 Heads | At least 1 Heads) $=\frac{P(3\ Heads\ \cap\ At\ least\ 1\ Heads)}{P( At\ least\ 1\ Heads)}$

$=\frac{\frac{1}{7} }{\frac{7}{8} } \\=\frac{1}{8}\times \frac{8}{7}\\ =\frac{1}{7}$

Thus, the probability that all three tosses land on heads given that at least one toss lands on heads is $\frac{1}{7}$ .

4 0

3 years ago

What is the answer???

qwelly [4]

The answer to your question is A

6 0

3 years ago

at a party 3/5 of the attendess were female . of the the female 2/5 wore earrings .what fraction of the attendees were femaleas

Nata [24]

$\frac{6}{25}$ of the attendees were females wearing earrings.

Step-by-step explanation:

As per the given information, there were $\frac{3}{5}$ females in the party.

To calculate the fraction of females wearing earrings we will do the following,

From these $\frac{3}{5}$ females, $\frac{2}{5}$ females wore earrings.

<u>This can be written in numerical form as:</u>

$\frac{2}{5}$ of $\frac{3}{5}$

---> $\frac{2}{5}$ * $\frac{3}{5}$

= $\frac{6}{25}$

So $\frac{6}{25}$ of the attendees were females wearing earrings.

Keywords: Fraction

Learn more about fractions at

#LearnwithBrainly

3 0

3 years ago

Use a proportion if two cassettes cost $14.50 How much will 15 cost

aev [14]

Cost/(number of cassettes) = $14.50/2 = x/15

Multiply by 15 to solve
15*($14.50/2) = x = $108.75

15 cassettes will cost $108.75.

8 0

4 years ago

What is the value of the expression 2.6 x 10 to the 9th power over 1.3 x 10 to the 2nd power?

yKpoI14uk [10]

2.6 * 10^9
-------------
1.3 * 10^2

2.6 / 1.3 = 2 and 10^9 / 10^2 = 10^7

so the answer is 2 * 10^7

4 0

4 years ago