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schepotkina [342]
3 years ago
11

One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant rate from 8 p.m. to midnight. At mi

dnight the temperature was −16.8 degrees.
What was the temperature at 9 p.m.?

Enter your answer in the box.
Mathematics
2 answers:
arsen [322]3 years ago
7 0

The correct answer is 4.2. This is because  -16.8 / 4 is -4.2 degrees.

  • Hoped this helped! :)

^-^

bearhunter [10]3 years ago
3 0
-4.2 degrees. What you would do is from 8-12 (midnight) is 4 hours. So it dropped -16.8 degrees in those 4 hours so -16.8 / 4 is -4.2 degrees. So it dropped -4.2 degrees every hour but it was also -4.2 degrees at 9:00 p.m.
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now... say... you have this angle here... let us find another that lands on that same spot

by simply just add 2π to it :)  

\bf \cfrac{7}{6}+2=\cfrac{19}{6}\qquad thus\qquad \cfrac{7\pi} {6}+2\pi =\cfrac{19\pi }{6}
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now, that's a positive one
and  \bf \cfrac{7}{6}-2=-\cfrac{5}{6}\qquad thus\qquad \cfrac{7\pi} {6}-2\pi =-\cfrac{5\pi }{6}
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to get more, just keep on subtracting or adding 2π


8 0
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Answer:

Step-by-step explanation:

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