Ten and five hundredths in decimal form is 10.05
The area of ΔIDK is 32.69 square units.
Solution:
Given data:
ID = 7 and Hypotenuse, KI = 11.67.
Let us first find KD:
Using Pythagoras theorem,




Subtract 49 from both sides.

Taking square root on both sides, we get
KD = 9.34
Area of the triangle = 

= 32.69
The area of ΔIDK is 32.69 square units.
6/50 = X/35 =
50x/210
210/50 =4.2
she can run 4.2 miles in 35 minutes
If a, b, c is an arithmetic sequence then a + c = 2b
a = 1/10; b = 3/20, c = 5/30
a + c = 1/10 + 5/30 = 3/30 + 5/30 = (3+5)/30 = 8/30
2b = 2 · 3/20 = 3/10 = 9/30
8/30 ≠ 9/30
If a, b, c is a geometric sequence then ac = b²
ac = 1/10 · 5/30 = 1/2 · 1/30 = 1/60
b² = (3/20)² = 9/400
1/60 ≠ 9/400
<span>Answer: Neither.</span>
Given:
The graph of an inequality.
To find:
The inequality for the given graph.
Solution:
From the given graph it is clear that the boundary line passes through the points (6,0) and (0,-4). So, the equation of the line is





The area under the boundary line is shaded and boundary line is a dotted line it means the points on the line are not included in the solution set. So, the inequality sing must be <.

Therefore, the required inequality for the given graph is
.