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3 years ago

7

A rectangular image of length 3 cm and width 4 cm is magnified in a studio. On magnification, 1 cm of the image represents 17 cm

. Find the perimeter of the rectangle in the magnified image.
Please help!
Answers:
576 cm
204 cm
408 cm
238 cm

1 answer:

alina1380 [7]3 years ago

6 0

Answer:

238 cm

Step-by-step explanation:

so we have a scale factor of 17: 1

originally we had the dimensions: 3cm by 4m

now we have 3*17 by 4*17 = 51 cm by 68 cm

Perimeter = 2*51 + 2*68 = 238 cm

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3.45 x 106

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i) 3*m*n + 7

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"3 times the product between two numbers, increased by 7"

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A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

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Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

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Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

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$=\frac{{n+1}}{4}[1+n}]$

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$=\frac{n^2+2n+1}{4}$

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Or we can write

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$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

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$\Rightarrow t = \frac{n-2}{2}+1$

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$\Rightarrow t = \frac{n}{2}$

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