We can use the compound interest formula
F=P(1+i)^n
where
F=Future value of investment to be found
P=present value of investment ($1000)
i=interest per period (1/4 year)=0.04/4=0.01
n=number of periods (3 years * 4 quarters = 12)
Substitute or "Plug in" values, so to speak,
F=1000*(1+0.01)^12
use a calculator to do the sum
=1126.83 (to the nearest cent, and use the proper rounding rules)
0 because the number in the middle is the midpoint.
Second: $500,000
Third: $250,000
Fourth: $125,000
Fifth: $62,500
Sixth:$31,250
Seventh:$15,625
If you need the total just add
Without scientific notation<span> it would look like 4 000 000 000 000 </span>
<span>The decimal place must be moved 12 units to the left to be after a significant figure, thus giving the scientific notation to the power of 12. The significant figure is 4 so you get the equation </span><span>4.0⋅<span>1012</span></span>.
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Answer:
(-8,4)
Step-by-step explanation:
Given: 2x-3y=-28 and x+6y=16
solve for a variable and then substitute back into other equation
x + 6y = 16
x = 16 - 6y; now use this in the other equation
2x - 3y = -28; substitute into x
2(16 - 6y) - 3y = -28; distribute 2
32 - 12y - 3y = -28; combine y's
32 - 15y = -28; isolate 15y
32 + 28 = 15y; add the numbers
60 = 15y; divide by 15
y = 4
Now use this to plug into other equation
x + 6y = 16; y=4
x + 6(4) = 16;
x + 24 = 16; subtract 24 from both sides
x = -8
