Answer:
The polynomial with real coefficients having zeros 2 and 2 - 2i is
x³ - 6x² + 16x - 16 = 0
Step-by-step explanation:
Given that a polynomial has zeros at 2 and 2 - 2i, we want to write this polynomial.
We have
x - 2 = 0
x - (2 - 2i) = 0
=> x - 2 + 2i = 0
Since the polynomial has real coefficients, and 2 - 2i is a zero of the polynomial, the conjugate of 2 - 2i, which is 2 + 2i is also a polynomial.
x - (2 + 2i) = 0
=> x - 2 - 2i = 0
Now,
P(x) = (x - 2)(x - 2 + 2i)(x - 2 - 2i) = 0
= (x - 2)((x - 2)² - (2i)²) = 0
= (x - 2)(x² - 4x + 8) = 0
= x³ - 4x² + 8x - 2x² + 8x - 16 = 0
= x³ - 6x² + 16x - 16 = 0
This is the polynomial required.
You can use the degree measure of the central angle theta (the number of degrees you have gone around the circle) and the amount of radians you have gone around the circle
the equation for arc length using degrees and radians is: s(arc length) = r(xº)
r is not the radius length it is the length you have gone around the circle measured in terms of the radius
you need to know the central angle (degrees) and radians to figure out arc length without knowing the radius length
That's the answer so i dont know how you do it!! Thats how i do it
Convert the decimal number to a fraction by placing the decimal number over power of ten. Since there are 3 numbers to the right of the decimal point, place the decimal number over 10^3 (1000). Then, add the whole number to the left decimal.
89 9/1000
