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kirza4 [7]
3 years ago
13

HELP PLEASE........ on these 2​

Mathematics
1 answer:
tester [92]3 years ago
8 0
For y=4 draw a horizontal line through the y-axis at point (0,4). Y-axis is the vertical.
For x=-3 draw a vertical line through the x-axis at point (-3,0). X-axis is the horizontal.
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3 years ago
The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays. Assuming the
AysviL [449]

Answer:

1.83% probability there are no car accidents on that stretch on Monday

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

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e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays.

This means that \mu = 4

What is the probability there are no car accidents on that stretch on Monday?

This is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4}*(4)^{0}}{(0)!} = 0.0183

1.83% probability there are no car accidents on that stretch on Monday

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3 years ago
Does this represent quntitites that are proportional
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What is the graph of this equation ​
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Step-by-step explanation:

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