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Natalija [7]
3 years ago
7

Sally got a new phone plan that includes limited data of 10 GB for $85, tax included. She has to pay $15 for each additional GB

used if she goes over her 10 GB allowed. Part A: Write an equation to describe her data plan where x represents each additional GB used.
Mathematics
1 answer:
natita [175]3 years ago
4 0

Answer:

Step-by-step explanation:

10Gb = 85 dollars

each 1gb =15 dollars

15 times x = 85

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What is the answer i really need help (−3)3 + (5 − 2)4
Katarina [22]
The answer to your question is 3
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Svetradugi [14.3K]
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3 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
Terrell hit a total of 10 home runs during the baseball season. He hit 4/5 of the of the homeruns during the first half of the s
deff fn [24]
To write this fraction as a decimal, what you must do in this case is to divide 4 by 5.
 Doing the division we have:
 4/5 = 0.8
 answer:
 the fraction of home runs hit during the first half of the season as a decimal is
0.8
5 0
3 years ago
Read 2 more answers
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