Ask question

Ask question

All categories

3 years ago

13

You invest an initial $1,000 in an account that has an annual interest rate of 2.5%, compounded annually. How much money will yo

u have in the account after 6 years? Round your answer to the nearest whole number.

2 answers:

Lyrx [107]3 years ago

7 0

The change is a growth of 2.5% so the factor will be:
1 + 0.025 = 1.025
N = 1000(1.025)⁶
= $1,160

snow_lady [41]3 years ago

5 0

1000(1+2.5%)^6=???????????

You might be interested in

Simplify 2^2[4+(3-6)^2]-13

HACTEHA [7]

Answer:

It's 19.

Step-by-step explanation:

Use order of operations (PEMDAS):

2^2[4+(3-6)^2]-13

Parentheses first:

= 2^2[4 + (-2)^2] - 13

= 2^2 ( 4 + 4) - 13

= 2^2 * 8 - 13

Now work out the exponent:

= 4*8 - 13

Now the multiplication:

= 32 - 13

= 19.

8 0

3 years ago

Here is a balanced hanger:

Slav-nsk [51]

I don't know exactly i think its either 3 grams or 7 grams or 2 1/2 grams

sorry if its wrong

3 0

3 years ago

Must choose a number between 55 and 101 that is a multiple of , 69, and 18 .

solong [7]

I'm certain there isn't a number that satisfies your conditions.
There's one multiple of 69 between 55 and 101: 69
And two multiples of 18 between 55 and 101: 72 and 90.

6 0

3 years ago

Read 2 more answers

Lillian is going to invest in an account paying an interest rate of 5.7% compounded continuously. How much would Lillian need to

Tems11 [23]

Answer: $5156

Step-by-step explanation:

Given

The rate of interest is 5.7%

time t=7 years

Amount after 7 years, $A=\$7600$

for compound interest, the Amount is given by

$\Rightarrow A=P(1+\frac{r}{100})^T$

Put values

$\Rightarrow 7600=P(1+0.057)^7\\\\\Rightarrow P=\dfrac{7600}{(1.057)^7}=5,155.71\\\\\Rightarrow P\approx \$5156$

5 0

3 years ago

PLZ HELP ME WITH THIS QUESTION!

PtichkaEL [24]

Answer:

The correct answer is A, 3,600 yards.

Step-by-step explanation:

7 0

2 years ago