What is the answer to the picture below

Brittany is asked about her age. She answers as follows. "My age is 10 more than twice the age of my younger brother." How old i

blagie [28]

Answer:

12

Step-by-step explanation:

x will be the age of her younger brother

34 = 2x + 10

She is ten more than twice his age

34 = 2x + 10

- 10 - 10

Then she twice his age

24 = 2x

÷2 ÷2

So his age is 12

x = 12

6 0

3 years ago

Subtract. 1 1/3−6 Enter your answer as a simplified mixed number by filling in the boxes IF YOU GET THIS RIGHT ILL GIVE BRAINLES

Vesnalui [34]

Answer:

$-4\frac{2}{3}$

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is the answer

Mrac [35]

Answer:

The coordinates of H′ are (-2,0).

Step-by-step explanation:

It is given that square EFGH stretches vertically by a factor of 2.5 with respect to the x-axis to create rectangle E′F′G′H′.

If a figure stretches vertically by a factor of 2.5 with respect to the x-axis, then the x-coordinates remains same and the points which lie on the axis are also remains the same after stretch.

It is given that the coordinates of H are (-2,0). This point lie on the x-axis, therefore it will remains the same after stretch.

Therefore the coordinates of H′ are (-2,0).

3 0

2 years ago

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What is 6(x+4)? Show work

natulia [17]

We will use distribution

we will multiply 6 to each variable and number in the parenthesis.
6 times x plus 6 times 4
which is 6x +24

8 0

2 years ago

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Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$