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3 years ago

What is the answer to the picture below

Mathematics

1 answer:

KengaRu [80]3 years ago

6 0

I believe your answer is C

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35 x 2/7 <br> 14, 5, 7, 10,

dlinn [17]

Answer:

Step-by-step explanation:

35 * 2/7

Rewriting

35/7 *2

5*2

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3 years ago

Dan earns $42.75 per month working as a tutor. He worked as a tutor for 4 months. He also earned $52.45 walking dogs in the neig

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Step 3. Dan added the last value $18.50 that he spent instead of subtracting from his earnings.

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4 years ago

Find the angle between vector u=2i+sqrt(11)j and v=-3i-2j to the nearest degree

const2013 [10]

Answer: Last option 155°

Step-by-step explanation:

We have the components of the vectors u and v.

Then, to find the angle between them, perform the following steps:

1) Calculate the scalar product u * v

If $u = 2i + \sqrt{11}j$ and $v = -3i-2j$

Then, the product scalar u * v is:

$u * v = (2)(-3) + (\sqrt{11})(-2)$

$u * v = -6-2\sqrt{11}$

$u * v = -12.633$

2) Calculation of the magnitude of both vectors.

$| u | = \sqrt{(2) ^ 2 + (\sqrt{11})^2}\\\\| u | = \sqrt{4+11}\\\\| u | = \sqrt{15}$

$| v | = \sqrt{(- 3) ^ 2 + (- 2) ^ 2}\\\\| v | = \sqrt{9 +4}\\\\| v | = \sqrt{13}$

3) Now that you know the product point between the two vectors and the magnitude of each, then use the following formula to find an angle

$u * v = | u || v |cos(\alpha)$

$-12.633 = \sqrt{15}\sqrt{13}*cos(\alpha)\\\\cos(\alpha) = \frac{-12.633}{\sqrt{15}\sqrt{13}}\\\\arcos(\frac{-12.633}{\sqrt{15}\sqrt{13}}) = \alpha\\\\\alpha =155\°$

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4 years ago

Olivia bought snacks for her team's practice. She bought a bag of popcorn for $3.39

NeTakaya

The answer is D because of the price range and the bag of popcorn not being multiplied by 4

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3 years ago

A student has 3 sticks of wood that measures 15 inches, 18 inches, and 30 inches. Can the student use these sticks to make a rig

mixer [17]

Answer:no

Step-by-step explanation:

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3 years ago