Answer:
Brownies made the most money
Step-by-step explanation:
Let c = cookies
b = brownies
We sold 51 items so c+b = 51
Cookies are .75 and brownies are 1.25
.75c + 1.25 b = 53.25
We have 2 equations and 2 unknowns
c = 51-b
Substituting into the second equation
.75(51-b) + 1.25b = 53.25
Distribute
38.25-.75b +1.25b = 53.25
Combine like terms
38.25+.5b = 53.25
Subtract 38.25 from each side
38.25 +.5b -38.25 = 53.25 -38.25
.5b =15
Divide each side by .5
.5b/.5 = 15/.5
b = 30
Now find c
c =51-b
c = 51-30
c = 21
They sold 30 brownies and 21 cookies
30 brownies * 1.25 =37.50
21 cookies *.75 = 15.75
Brownies made the most money
Answer:
y = 1 m = -3 b = 1
Step-by-step explanation:
y = mx + b y = -3x + 1
y = 1
m = -3
b = 1
(arrange the data set from least to greatest)
0, 0, 2, 2, 3, 4, 6, 8
(find the median: *the middle number*)
Median: 2.5
Lower quartile: 1
Upper quartile: 5
Interquartile range : upper quartile - lower quartile = answer
Interquartile range: 5 - 1 = 4
So the IQR or interquartile for the following data set is 4.
B. RSP and PST I’m pretty sure.
Answer:
0,250
Step-by-step explanation:
The probability that you looking for is sum of probability of getting someone in the 18-27age (74 persones) and probability to getting someone who refused (36 and 19 persones) - probability of getting some of 18-27 age who refused (36 persons).
The probability is:
P(a or b)= p(a)+p(b)-p(a&b)=74/371+(36+19)/371-36/371=0,199+0,148-0,097=0,250
