<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
The correct answer is 1,51%
Step-by-step explanation:
To get the probability equally likely of the first 6 examined that have a defective compressor, we use the following formula
P=# of possibilities that meet the condition / #of equally likely possibilities.
As there are multiple events , and all must be achieve, we multiply the probabilities.
P1=7 / 11
P2=6 / 10
P3=5 / 9
P4=4 / 8
P5=3 / 7
P6=2 / 6
P(x)=7 / 11*6 / 10*5 / 9*4 / 8*3 / 7*2 / 6=0,01515151515
P(x)=1,51%
Answer:
Hmm
Step-by-step explanation:
Answer:
Those areas are: A 1 = 12, A 2 = 19
Step-by-step explanation:
The area of shape 1 : it consists of 1 square + 4 right triangles
Area of the square: A = a², area of the triangle: A = 1/2 · a · h
A 1 = 2² + 4 · 1/2 · 2 · 2 = 4 + 8 = 12
The area of shape 2 : it consists of 2 isosceles triangles
A 2 = 1/2 · 2 · 4 + 1/2 · 6 · 5 = 4 + 15 = 19
